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Kipish [7]
3 years ago
15

one serving of a cookie recipe calls for 6 tablespoons of sugar. if one serving makes enough for 4 people, how much sugar is nee

ded to serve 10 people?
Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0
15 tablespoons of sugar is needed for 10 people
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Can someone please help me?
Andru [333]

Answer:

Use the SINE COSINE and the TANGENT rule

Step-by-step explanation:

1.1st use the Pythagoras theorem to find the value of the other side

2.Now be comfortable to use the rule............................

4 0
2 years ago
5 1/3 in decimal form​
STatiana [176]

Answer:

5.33

Step-by-step explanation:

5+1/3

=5.3333

=533.33333333%

7 0
3 years ago
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I feel like this is simple but i just forgot
Marrrta [24]

Answer:

Probably d but im d u mb

Step-by-step explanation:

3 0
3 years ago
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Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
3 years ago
Solve by elimination:<br> x + 9y = 8<br> -6X - 9y = -3
WITCHER [35]

Answer:

(-1,1)

Step-by-step explanation:

x + 9y = 8

-6x - 9y = -3

Add the two equations together to eliminate y

x + 9y = 8

-6x - 9y = -3

---------------------

-5x   = 5

Divide by -5

-5x/-5 = 5/-5

x = -1

Now solve for y by substituting into the first equation

x+9y = 8

-1 + 9y =8

Add 1 to each side

-1+1 + 9y = 8+1

9y=9

Divide each side by 9

9y/9 = 9/9

y = 1

5 0
3 years ago
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