Question

What is (3xy-1) (4xy+2)

Answer 1

Hello!

The answer is:

$(3xy-1)(4xy+2)=12(xy)^{2}+2xy-2$

or

$(3xy-1)(4xy+2)=12x^{2}y^{2}+2xy-2$

Why?

To solve the problem and identify the resultant expression, we need to apply the distributive property, and the, add or subtract like terms.

Describing the distributive property:

$(a+b)(c+d)=a*c+a*d+b*c+b*d$

Remember, like terms are the terms that share the same variable and same exponent, for example:

$a^{2} +3a^{2}+a^{3}=4a^{2}+a^{3}$

We were able to add only the terms that have the same exponent (2).

We are given the expression:

$(3xy-1)(4xy+2)$

Now, solving we have:

$(3xy-1)(4xy+2)=(3xy*4xy)+(3xy*2)-(1*4xy)-2\\\\(3xy*4xy)+(3xy*2)-(1*4xy)-2=12(xy)^{2}+6xy-4xy-2\\\\12(xy)^{2}+6xy-4xy-2=12(xy)^{2}+2xy-2$

Hence, we have that:

$(3xy-1)(4xy+2)=12(xy)^{2}+2xy-2$

or

$(3xy-1)(4xy+2)=12x^{2}y^{2}+2xy-2$

Have a nice day!

Answer 2

12x^2y^2+2xy-2 with problems like these use the app “Photomath” it will help you a lot.