A good place to start is to set
to y. That would mean we are looking for
to be an integer. Clearly,
, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since
is a radical, it only outputs values from
, which means y is on the closed interval:
.
With that, we don't really have to consider y anymore, since we know the interval that
is on.
Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval
, which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.
Answer:the measure of angle 6 is 60 degrees.
Step-by-step explanation:
The two horizontal lines ate straight and parallel lines. It is established that the sum of the angles on a straight line is 180 degrees. Looking at the given figure, angle 5 and angle 6 are on a straight line. Therefore
Angle 5 + angle 6 = 180 degrees. Therefore,If angle 5 is 120 degrees,then
Angle 6 + 120 = 180
Angle 6 = 180 - 120 = 60 degrees.
Answer:
Ok y= 2x + b
b referring to any number less than -2 and more than -2
so y=2x+4 can work
Step-by-step explanation:
parallel lines in slope-intercept form have the same slope, i.e. the same 'm' value or coefficient of <em>x</em><em> </em> but different interceptions
Options:
(2, 2), (3, 1), (4, 2)
(2, 2), (3, –1), (4, 1)
(2, 2), (1, –2), (0, 2)
(2, 2), (1, 2), (2, 0)
Answer:
A. (2, 2), (3, 1), (4, 2)
Step-by-step explanation:
Given


Required
Solve for x and y
To solve this, we make use of graphical method (see attachment for graph)
All points that lie on the shaded region are true for the inequality
Next, we plot each of the given options on the graph
A. (2, 2), (3, 1), (4, 2)
All 3 points lie on the shaded region.
<em>Hence, (a) is true</em>