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kati45 [8]
3 years ago
10

If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answ

er to the nearest hundredth. triangles ABC and ADC in which angle C is a right angle, point D is on segment BC between points B and C, the measure of angle ABD is x degrees, and the measure of angle ADC is y degrees 0.74 units 1.17 units 1.64 units 2.14 units
Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

  1.17 units

Step-by-step explanation:

From the definition of the sine of an angle, you know ...

  sin(45°) = AC/AB = 4/AB   ⇒   AB = 4/sin(45°) ≈ 5.6569

  sin(63°) = AC/AD = 4/AD   ⇒   AD = 4/sin(63°) ≈ 4.4893

Then the difference AB-AD is ...

  AB -AD = 5.6569 -4.4893 = 1.1676

  AB -AD ≈ 1.17 units

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The mass of the apple juice needed to increase the initial concentration to 25% is 45 kg

The given parameters;

  • <em>Mass of the apple juice, m = 30 kg</em>
  • <em>current percentage, = 10%</em>
  • <em>final percent after increment = 25%</em>

Let the mass added to increase the percentage to 30% = x

10% ----------------- 30 kg

25% ------------------ ?

= \frac{25 \times 30}{10} \\\\= 75 \ kg

The additional mass is calculated as;

x+ 30 = 75\\\\x = 75 - 30\\\\x = 45 \ kg

Thus, the mass of the apple juice needed to increase the initial concentration to 25% is 45 kg.

Learn more about percentage and ratio here: brainly.com/question/11752721

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You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

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Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

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