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3 years ago

What does the gradient of a distance time graph show?

1 answer:

7 0

<span>The gradient of a distance-time graph represents the speed of an object. The velocity of an object is its speed in a particular direction. The slope on a velocity-time graph represents the acceleration of an object. The distance travelled is equal to the area under a velocity-<span>time graph</span></span>

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At time t0 = 0 the mass happens to be at y0 = 4.05 cm and moving upward at velocity v0 = +4.12 m/s. (Mind the units!) Calculate

Katen [24]

Answer:

A = 5.727 cm

Explanation:

at time t = 0s the displacement of mass is 4.05 cm and velocity 4.12 m/s

we know that velcoity for simple harmonic motion is given as

$v_o = \omega \sqrt {A^2 - Y_O^2}$

W KNOW THAT

$\omega = \frac{v_0}{Y_o}$

Therefore we get

$Y_O^2 = A^2 - Y_O^2$

$A =\sqrt 2 * Y_O$

$A =\sqrt 2 * 4.05\\$

A = 5.727 cm

4 0

3 years ago

A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this

wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

$r=r_o\times A^{\frac{1}{3}}$

$r_o=1.25 \times 10^{-15} m$ = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

$r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}$

$r=4.6656\times 10^{-15} m=4.6656 fm$

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) $F=k\times \frac{q_1q_2}{a^2}$

k= $9\times 10^9 N m^2/C^2$ = Coulombs constant

$q_1,q_2$ = charges kept at distance 'a' from each other

F = electrostatic force between charges

$q_1=+1.602\times 10^{-19} C$

$q_2=+1.602\times 10^{-19} C$

Force of repulsion between two protons on opposite sides of the diameter

$a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m$

$F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}$

$F=2.6527 N$

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

6 0

3 years ago

What is one way wind or water change the earth?

insens350 [35]

Answer:

water hydrates the earth's soil....

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3 years ago

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PLEASE HELP NOW!! Which of the following must be the same for two isotopes of an element?

Masteriza [31]

B. The atomic number

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4 years ago

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Explain the different methods that can be used to model the motion of an object.

Simora [160]

Answer:

You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. idk if this helps.

Explanation:

5 0

3 years ago

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