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3 years ago

A jet airliner moving initially at 852 mph

Physics

1 answer:

jekas [21]3 years ago

7 0

Answer:

984.8 mph

Explanation:

The initial velocity of the jet in terms of components is

$v_x = 852 mph\\v_y = 0$

where we took east as positive x-direction and north as positive y-direction.

The velocity of the wind is

$v'_x = (206)(cos 55^{\circ})=118.2 mph\\v'_y = (206)(sin 55^{\circ})=168.7 mph$

So, the resultant velocity of the jet considering also the wind is

$V_x = v_x + v'_x = 852+118.2=970.2 mph\\V_y = v_y + v'_y = 0 + 168.7 =168.7 mph$

And so the new speed of the jet is

$V=\sqrt{V_x^2+V_y^2}=\sqrt{(970.2)^2+(168.7)^2}=984.8 mph$

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An object moves in simple harmonic motion described by the equation d equals one fifth sine 2 t where t is measured in seconds a

tensa zangetsu [6.8K]

Answer:

The maximum displacement, the frequency, and the time required for one cycle are 1/5 inch, 1/π Hz and π sec.

Explanation:

Given that,

The equation of simple harmonic motion

$d = \dfrac{1}{5}\sin 2t$ .....(I)

We need to calculate the maximum amplitude

Using equation of simple harmonic motion

$y = a \sin\omega t$

Where, a = amplitude

$\omega$ =frequency

t = time

On comparing equation (I) and general equation

The amplitude is a maximum displacement traveled by a wave.

$a = \dfrac{1}{5}$

So, the maximum displacement is

$d= \dfrac{1}{5}\ inch$

We need to calculate the frequency

$\omega=2\pi f$

$f = \dfrac{1}{\pi}\ Hz$

We need to calculate the time required for one cycle

$t =\dfrac{1}{f}$

$t =\pi\ sec$

Hence, The maximum displacement, the frequency, and the time required for one cycle are 1/5 inch, 1/π\ Hz and π\ sec.

3 0

3 years ago

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh

frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

$y\propto x^{1.25}$

$y=kx^{1.25}$

$k=\dfrac{y}{x^{1.25}}$

Put the value into the formula

$k=\dfrac{1.8}{1.1^{1.25}}$

$k=1.5978$

We need to calculate the crab weight

$y=kx^{1.25}$

Here, x = 0.85 g

Put the value into the formula

$y=1.5978\times(0.85)^{1.25}$

$y=1.3040\ gram$

Hence, The weight of body is 1.3040 gram.

7 0

4 years ago

A high school physics student claims her muscle car can achieve a constant acceleration of 10 ft/s/s. Her friend develops an acc

Nikolay [14]

Answer: Ф = 17.2657 ≈ 17°

Explanation:

we simply apply ET =0 about the ending of the rod

so In.g.L/2sinФ - In.a.L/2cosФ = 0

g.sinФ - a.cosФ = 0

g.sinФ = a.cosФ

∴ tanФ = a/g

Ф = tan⁻¹ a / g

Ф = tan⁻¹ ( 10 / 32.17405)

Ф = tan⁻¹ 0.31080948777

Ф = 17.2657 ≈ 17°

Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°

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3 years ago

Of the following gases, ________ will have the greatest rate of effusion at a given temperature.

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3 years ago

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I feel dvmb for asking this question but... help? Please?

VMariaS [17]

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3 years ago