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lyudmila [28]
3 years ago
12

A jet airliner moving initially at 852 mph

Physics
1 answer:
jekas [21]3 years ago
7 0

Answer:

984.8 mph

Explanation:

The initial velocity of the jet in terms of components is

v_x = 852 mph\\v_y = 0

where we took east as positive x-direction and north as positive y-direction.

The velocity of the wind is

v'_x = (206)(cos 55^{\circ})=118.2 mph\\v'_y = (206)(sin 55^{\circ})=168.7 mph

So, the resultant velocity of the jet considering also the wind is

V_x = v_x + v'_x = 852+118.2=970.2 mph\\V_y = v_y + v'_y = 0 + 168.7 =168.7 mph

And so the new speed of the jet is

V=\sqrt{V_x^2+V_y^2}=\sqrt{(970.2)^2+(168.7)^2}=984.8 mph

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Chứng minh V=kq/r từ mối liên hệ giữ E và V
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Answer:V=Aq=KQr

Explanation:

Không biết V bạn kí hiệu ở đây là gì nhỉ? Có phải là điện thế?

Điện thế tại 1 điểm trong điện trường được định nghĩa là công làm vật dịch chuyển từ vị trí đó đến vô cùng. V = A/q

Chứng minh thì được, nhưng chỉ e bạn không có hiểu biết về nguyên hàm, tích phân nên không hiểu.

- Xét tại vị trí cách điện tích Q một đoạn x, khi đó điện tích q sẽ chịu 1 lực: dF=KQ.qx2

Điện tích q dịch chuyển 1 khoảng dx rất nhỏ. Khi đó công do lực điện trường gây ra là:

dA=dF.dx=KQ.qx2dx

Công để dịch chuyển điện tích q từ vị trí r đến vô cùng là:

A=∫∞rdA=∫∞rKQ.qx2dx=KQ.qr−KQ.q∞=KQ.qr

Theo đúng định nghĩa: V=Aq=KQr

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