Pls answer fast and correct i will give brainlest who ever gets it correct

1 answer:

7 0

The boys body will continue to move in a forward motion, the stairs an an will make the skateboard come to a complete stop because the force of the stairs is much greater, this makes in an unbalanced force. This is and example of inertia of motion.

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What is a group of individuals of the same species living in the same geographic area

balu736 [363]

A group of individuals living in a particular geographic area is termed population.

8 0

3 years ago

The linear momentum of a truck of mass 5000 kg that is moving at a velocity of +30 m/a is ___ kg m/s

miv72 [106K]

Linear momentum of a truck is 1,50,000 kg.m/s

Explanation:

Linear momentum is the product of the mass and velocity of an object. It is a vector quantity, which have a magnitude and a direction.

Linear momentum is a property of an object which is in motion with respect to a reference point (i.e. any object changing its position with respect to the reference point).

It's SI units are kg.m/s

Linear momentum is a vector quantity.

Linear momentum formula (p) = mass × velocity

Given data mass = 5000 kg ; velocity = 30 m/s

P = 5000 × 30

Linear momentum p= 1,50,000 kg.m/s

7 0

3 years ago

Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis

solong [7]

Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

$v^{2}=u^2+2as$

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

$v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s$

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

$v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds$

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equals $T=2\times 30.51\approx61seconds$