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HACTEHA [7]
3 years ago
14

Please help me find the equation xx

Mathematics
1 answer:
Lisa [10]3 years ago
8 0

9514 1404 393

Answer:

  • (2x-10) +x +(x+10) = 180
  • x = 45
  • (2x-10)° = 80°
  • (x+10)° = 55°
  • x° = 45°

Step-by-step explanation:

The equation is an expression of the fact that <em>the sum of the angles in a triangle is 180°.</em>

  (2x -10)° +x° +(x +10)° = 180°

For the purposes of the answer box, I'd leave off the degree symbol:

  (2x -10) +x +(x +10) = 180

__

This simplifies to ...

  4x = 180

  x = 45

Then the angles (CW from top) are ...

  (2·45 -10) = 80°

  (45 +10)° = 55°

  (45)° = 45°

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Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

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(a)

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P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

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Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

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