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Ludmilka [50]
4 years ago
11

Which of the following statements are true? (Select all that apply.) Ammeters have a relatively high resistance and are placed i

n parallel with a resistor. Ammeters have a very low resistance and are placed in series with a resistor. Ammeters have a very low resistance so as to not significantly alter the total resistance of a circuit. Voltmeters have a relatively high resistance and are placed in parallel with a resistor. Ammeters have a relatively high resistance and are placed in series with a resistor. Voltmeters have a relatively high resistance and are placed in series with a resistor. Ammeters have a relatively low resistance and are placed in parallel with a resistor. Voltmeters have a very low resistance and are placed in series with a resistor. Voltmeters have a very low resistance and are placed in parallel with a resistor.
Physics
1 answer:
xenn [34]4 years ago
5 0

Answer: Ammeters have a very low resistance and are placed in series with a resistor.

Ammeters have a very low resistance so as to not significantly alter the total resistance of a circuit.

Voltmeters have a relatively high resistance and are placed in parallel with a resistor.

Explanation: An ammeter is a device which used to measure current in a circuit. Thus, it is placed in series with the other components of the circuit. In series, the current remains same throughout the circuit and depends on the net resistance of the circuit.

This, the ammeter must have very low resistance so that it doesn't alter the net resistance of the circuit.

A voltmeter is a device which is used to measure potential drop across a component in a circuit. Thus, it is placed in parallel combination to to the component. The resistance of a voltmeter must be high so that no current flows through it and alters the potential drop across the component.

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The mass number minus the atomic number is equal to the number of
iVinArrow [24]

Answer:

neutron

Explanation:

5 0
3 years ago
An ordinary flashlight uses two D cells 1.50 V batteries connected in series. The bulb draws 380 m???? when turned on.
melamori03 [73]

Answer:

a. 7.89 Ω, 1.14 W

b. By a factor of 2; The batteries would heat up.

Explanation:

a. Using Ohm's law, we have that Voltage, V, is directly proportional to Current, I, with the constant of proportionality being Resistance, R. Mathematically:

V = IR

The voltage of the two batteries would be:

V = V1 + V2 = 1.5 + 1.5 = 3.0 V

The current is 380 mA = 0.38 A

Hence, the Resistance, R, will be:

R = \frac{V}{I}

R = \frac{3}{0.38}

R = 7.89 Ω

Power is given as:

P = IV

P = 3 * 0.38

P = 1.14 W

b. If the batteries are now 4, the new voltage will be:

V = 4 * 1.5

V = 6 V

Power becomes:

P = 0.38 * 6

P = 2.28 W

Comparing with Power in (a) above, we see that the new Power is double the value of the former Power. Hence, the Power has increased by a factor of 2.

It is not advisable to use double the number of batteries to power a flashlight because it would cause the batteries to heat up and thereby, leak or in the worst case scenario, blow up. This could be damaging to the flashlight.

3 0
3 years ago
8. What is the weight in newtons of a 10 kg mass on the earth's surface?
iogann1982 [59]
Weight = Mass times Acceleration due to gravity.

Weight = 10 kg times 9.8 m/s^2

Weight = 98 kg
7 0
3 years ago
A water wave traves with a length of 10 meters and a frequency of 30 hertz, what is the velocity of the wave?
UNO [17]

Answer: 300 m/s

Explanation:

Given that:

length of water wave (λ) = 10 metres

Frequency of water wave (F) = 30 Hertz

Velocity of water wave (V) = ?

The velocity of a wave is the distance covered by the wave in one second. It is measured in metre per second, and represented by the symbol V. It is related to frequency and wave length by the formula: V = F λ

V = 30 Hertz x 10 metres

V = 300 m/s

Thus, the velocity of the water wave is 300 m/s

4 0
3 years ago
in 1984 don, disk that stayed aloft for 16.7 seonds supsuppose cain ran up a staricase during this time, reachig a height of 18.
laila [671]

Answer

given,

time of disk stayed a loft = 16.7 sec

height reached = 18.4 m

mass  = 72 kg

now work done is equal to change in potential energy

W = - (U_f - U_i)

W = - (mgh - 0)

W = - (72\times (-9.8) \times 18.4)

W = 12983.04 J

Positive sign means that work is in the direction of motion.

Power = \dfrac{Work\ done}{time}

Power = \dfrac{W}{t}

Power = \dfrac{12983.04}{16.7}

P = 777.42 Watts

8 0
3 years ago
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