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antiseptic1488 [7]

3 years ago

8

Which of the following statements best represents a comparison of the two motions shown on the graph?

1 answer:

guajiro [1.7K]3 years ago

8 0

Answer:

C. the top line represents a greater velocity

Explanation:

The graph is a distance - time graph.

The distance is on the y-axis and time is on the x - axis.

For this graph, the slope is the velocity.

The steeper the line, the higher the velocity or the higher the slope.
Since the upper line is steeper, it will have a higher slope
Hence a greater velocity

The lower line is not so steep and its slope is lesser compared to the upper one.

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Select the correct answer.

Nina [5.8K]

Answer:

Ос.

The spacing between particles increases.

Heat causes greater particle activity, and the particles

are farther apart.

3 0

3 years ago

A 10 kg mass stretches a spring 70 cm in equilibrium. Suppose a 2 kg mass is attached to the spring, initially displaced 25 cm b

NARA [144]

Answer:

Explanation:

1. Find spring constant k. From a free body diagram, you will get the forces on the 10 kg mass, with a displacement d. It will be gravity pulling the mass down and the spring force pulling the mass up. The 10 kg mass is in equilibrium. The resulting equation will be:

$F = m_1a = kd - m_1g = 0 => m_1g = kd => k = \frac{m_1g}{d}$

2. Use the result from 1. to find the equations of motion. In general they are given by:

$x(t) = Acos(\omega t + \phi), v(t) = -\omega Asin(\omega t + \phi)$ , where ω is: $\omega = \sqrt{\frac{k}{m_2}}=\sqrt{\frac{m_1g}{m_2d}}$

To find the amplitude A and the phase angle Ф, use the given initial conditions:

m₂ = 2 kg, x(0) = -0.25 m, v(0) = 2m/s

$-0.25 = Acos(\phi)\\2 = -\omega Asin(\phi)= -\sqrt{\frac{m_1g}{m_2d}}Asin(\phi)\\-0.24 = Asin(\phi)$

Solving for Ф:

$\frac{0.24}{0.25}=tan(\phi) => \phi = 0.76$

Solving for A:

$-0.25 = Acos(\phi) => A = -\frac{0.25}{cos(\phi)}=-0.35$

The equation for x(t) is now:

$x(t) = -0.35 cos(\sqrt{\frac{m_1g}{m_2d}t} +0.76)$

The frequency f is given by: $f = \frac{\omega}{2\pi}$

The period T is given by: $T = \frac{2\pi}{\omega}$

8 0

3 years ago

On a frictionless plane inclined at angle 303. The box is connected via a cord of negligible mass to a box of laundered money (m

KATRIN_1 [288]

Answer:

T = 1.73 kg

Explanation:

Let's use Newton's second law for this balance problem

We draw a coordinate system with the x axis parallel to the plane and the Y axis perpendicular

The only force we have to lay down is the weight (W)

Wx = W sin θ

Wy = W cos θ

Wx = 2.0 ain 60

Wx = 1.73 kg

Wy = 2.0 cos 60

Wy = 1.0 kg

Y Axis

N-Wy = 0

X axis

T- Wx = 0

T = Wx

T = 1.73 kg

7 0

3 years ago

You are driving at the speed of 33.4 m/s (74.7296 mph) when suddenly the car in front of you (previously traveling at the same s

romanna [79]

Answer:

Part a)

a = - 8.45 m/s/s

Part b)

$d = 66 m$

Part c)

$d = 14.16 m$

Explanation:

Part a)

when car apply brakes then the friction force on the car in front of us is given as

$F_f = \mu mg$

here we need to find deceleration due to friction

$a = \frac{F_f}{m}$

$a = -\mu g$

$a = -8.45 m/s^2$

Part b)

Braking distance of the car is the distance that it move till it stops

so we will have

$v_f^2 - v_i^2 = 2ad$

$0 - 33.4^2 = 2(-8.45)d$

$d = 66 m$

Part c)

Since we know that average reaction time for human is 0.424 s

now we know that during reaction time our car will travel at uniform speed

so we will have

$d = vt$

$d = (33.4) (0.424)$

$d = 14.16 m$

4 0

3 years ago

AKS 8a - Phenomena-Based Question: Use the data and the graph to make a claim as to which person represents each letter on the g

sergeinik [125]

Answer:

,mhom

Explanation:

6 0

3 years ago