Which of the following statements best represents a comparison of the two motions shown on the graph?

Physics

1 answer:

guajiro [1.7K]3 years ago

8 0

Answer:

C. the top line represents a greater velocity

Explanation:

The graph is a distance - time graph.

The distance is on the y-axis and time is on the x - axis.

For this graph, the slope is the velocity.

The steeper the line, the higher the velocity or the higher the slope.
Since the upper line is steeper, it will have a higher slope
Hence a greater velocity

The lower line is not so steep and its slope is lesser compared to the upper one.

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What did you notice about the angle of incidence and the angle of reflection?

Readme [11.4K]

Answer:

They are equal

Explanation:

angle of incidence = angle of reflection

6 0

2 years ago

I was driving along at 20 m/s, trying to change a CD and not watching where I was going. When I looked up, I found myself 45 m f

cricket20 [7]

Answer:

$a=4.44\frac{m}{s^2}$

Explanation:

First we have to find the time required for train to travel 60 meters and impact the car, this is an uniform linear motion:

$t=\frac{d}{v}\\\\t=\frac{60m}{30\frac{m}{s}}=2s$

The reaction time of the driver before starting to accelerate was 0.50 seconds. So, remaining time for driver is 1.5 seconds.

Now, we have to calculate the distance traveled for the driver in this 0.5 seconds before he start to accelerate. Again, is an uniform linear motion:

$d=vt\\d=20\frac{m}{s}(0.5s)=10m$

The driver cover 10 meters in this 0.5 seconds. So, the remaining distance to be cover in 1.5 seconds by the driver are 35 meters. We calculate the minimum acceleration required by the car in order to cross the tracks before the train arrive, Since this is an uniformly accelerated motion, we use the following equation:

$d=v_0t+\frac{1}{2}at^2\\a=\frac{2(d-v_0t)}{t^2}\\a=\frac{2(35m-20\frac{m}{s}*1.5s}{(1.5s)^2}\\a=4.44\frac{m}{s^2}$