Torque is equal position vector times (r) times force vector
(F). Since F= 10 N and r = 0.1 m, so the
torque is equal to (10 N) x ( 0.1 m) = 1Nm. The direction of the torque would
be into the screen, clockwise rotation.
Answer: 1.5×10^10 N/C
Explanation:
E= F/q
Where E= magnitude of the electric field
F= force of attraction
q= charge of the given body
Given F= 6.5×10^-8 N
q= 4.3× 10^-18 C
Therefore, E = 6.5×10 ^-8/ 4.3×10^-18
E = 1.5×10^10 N/C
Answer:
-4.71 m/s
Explanation:
Given:
y₀ = 1.13 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.13 m)
v = -4.71 m/s
The applied force is different for the two cases
The case A with a greater force involves the greatest momentum change
The case A involves the greatest force.
<h3>What is collision?</h3>
- This is the head-on impact between two object moving in opposite or same direction.
The initial momentum of the two ball is the same.
P = mv
where;
- m is the mass of each
- v is the initial velocity of each ball
Since the force applied by the arm is different, the final velocity of the balls before stopping will be different.
Thus, the final momentum of each ball will be different
The impulse experienced by each ball is different since impulse is the change in momentum of the balls.
J = ΔP
The force applied by the rigid arm is greater than the force applied by the relaxed arm because the force applied by the rigid arm will cause the ball to be brought to rest faster.
Thus, we can conclude the following;
- The applied force is different for the two cases
- The case A with a greater force involves the greatest momentum change
- The case A involves the greatest force.
Learn more about impulse here: brainly.com/question/25700778
The density of ice is less than the density of water. C
