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butalik [34]
3 years ago
15

Choose the best unit of measure to find the capacity of a swimming pool.

Mathematics
1 answer:
Nady [450]3 years ago
4 0
Kiloliters.Hope I helped.
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Using the Principle of Mathematical Induction, prove that . n ^2 − n is even for n ≥ 1​
Tamiku [17]

Base case: if <em>n</em> = 1, then

1² - 1 = 0

which is even.

Induction hypothesis: assume the statement is true for <em>n</em> = <em>k</em>, namely that <em>k</em> ² - <em>k</em> is even. This means that <em>k</em> ² - <em>k</em> = 2<em>m</em> for some integer <em>m</em>.

Induction step: show that the assumption implies (<em>k</em> + 1)² - (<em>k</em> + 1) is also even. We have

(<em>k</em> + 1)² - (<em>k</em> + 1) = <em>k</em> ² + 2<em>k</em> + 1 - <em>k</em> - 1

… = (<em>k</em> ² - <em>k</em>) + 2<em>k</em>

… = 2<em>m</em> + 2<em>k</em>

… = 2 (<em>m</em> + <em>k</em>)

which is clearly even. QED

8 0
3 years ago
The discriminate of a quadratic is given as b² - 4ac is equal to 0. Select the best description below.
zzz [600]

Answer:

2) the quadratic has one x intercept

Step-by-step explanation:

D = 0 => has twin quadratics as one x intercept

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2 years ago
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6 0
3 years ago
Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
Find the unit rate. $9.30 for 3 gallons
bonufazy [111]

Answer: $3.10 per gallon

Step-by-step explanation: 9.30 divided by 3

7 0
2 years ago
Read 2 more answers
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