Answer:
The profit will be maximum on x = 250.
Step-by-step explanation:
From the given information:
Revenue = 1500x - x²
Cost = 1500 + 1000x
As we know that
Profit = Revenue - Cost ; Let say it equation 1
Then after putting the values of revenue and cost in equation 1 we have:
Profit = (1500x - x²) - (1500 + 1000x)
Profit = 1500x - x² - 1500 - 1000x
Profit = -x² + 500x - 1500
We know that at the max or min the slope of the graph formed by the profit function will be zero, therefore we find the slope of profit function by taking the first derrivative w.r.t. x as under:
d(Profit)/dx = d/dx(-x² + 500x - 1500)
d(Profit)/dx = -2x + 500
By putting the above slope equal to zero we get:
d(Profit)/dx = -2x + 500 = 0
-2x + 500 = 0
-2x = -500
x = 250
Therefore it is concluded that the profit will be maximum when x will be equal to 250.
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Did the question get cut off?
a = -(1/5)
b = 1
c = 0
Step-by-step explanation:
y = x/5 may be rewritten as y = (1/5)x
y = (1/5)x
y - (1/5)x = 0
- (1/5)x + y + 0 = 0
ax + by + c = 0
a = -(1/5)
b = 1
c = 0
So let's say he was earring x before his raise. That means that:
x times 1.09 = 654 (1.09 represents 100% (this is the 1.0) of his original salary plus 9% (this is the .09) his raise.
So,
1.09x = 654; now divide both sides by 1.09 to isolate and solve for x, and you get x = $600.
