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Alisiya [41]
2 years ago
5

PLZ HELLLP 50 POINTS, WILL GIVE BRAINLY PLZZZZZZZZZZ

Mathematics
2 answers:
ki77a [65]2 years ago
7 0

<u>Answer:</u>

<em>Transgenic Organism</em>

<u>My reasoning:</u>

<u />

A transgenic organism is an organism which has been modified with genetic material from another species. The biggest use of transgenic organisms is for agriculture growth, the development of genetically modified crops.

They also research with transgenic mice. Mice can be modified with human DNA for the purpose of testing medical treatments and seeing how they might behave in a human.

Researchers are concerned though that interbreeding between transgenic and wild organisms could have unforeseen consequences and could reign havoc on our ecosystem.

<em>~That's All Folks~</em>

<em>-Siascon</em>

Ludmilka [50]2 years ago
4 0

transgenic organisms is the answer

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Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
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Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

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Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

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because just do the math bu bl I really dk

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