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3 years ago

I need help remembering the steps to solve

Mathematics

2 answers:

Viefleur [7K]3 years ago

4 0

Take a common point ( C in this case)
1. Take the difference of the y coordinates from the point vertical to C.
C from D in this case.
2.Take the diff of the x coordinates from the points horizontal to the first.
C from B in this case.
3. Now add the diff to the common point. X to x Y to y.

aliina [53]3 years ago

3 0

Picture is sloppy cant see it for real

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A diver went 25.65 feet below the surface of the ocean and then 16.5 feet further down he then rose 12.45 feet write and solve a

Anastaziya [24]

So a diver went 25.65 ft BELOW so it's negative.
then he went 16.5 ft further down, so that's negative also.
he then rose 12.45 ft, so that's positive.
so the expression is: -25.65+-16.5+12.45, the answer is 23.7

8 0

2 years ago

A 6-sided die is rolled. what is the probability of rolling a number less than 4?

ohaa [14]

1/2

Step-by-step explanation:

All outcomes of a single die= 6

Events less than 4 =3

probability=3/6

=1/2

7 0

1 year ago

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antoniya [11.8K]

I hope this helps :)

Your welcome

4 0

1 year ago

Read 2 more answers

an insurance company sells a policy that pays $50,000.00 in case of accidental death. According to company figures, the rate of

aliya0001 [1]

Answer: $23..50 see attachment for the explanation.

5 0

2 years ago

????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered

Karolina [17]

By Green's theorem, the integral of $\vec F$ along $C$ is

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy$

which is 6 times the area of $D$ , the region with $C$ as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle $\theta$ and radius $r$ , the area $A$ of the sector is proportional to the circle's overall area according to

$\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3$

so that the value of the integral is

$\dfrac{6\times8\pi}3=\boxed{16\pi}$

6 0

3 years ago