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3 years ago

Lesson 6.2 math 7th grade

Mathematics

2 answers:

Darina [25.2K]3 years ago

7 0

There is not a image or a url to know what are u talking about ?

Daniel [21]3 years ago

5 0

What about lesson 6.2 math 7th grade??

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Which expression is equivalent to 3(4m - 5)?

77julia77 [94]

Answer:

D. 12m-15

Step-by-step explanation:

3(4m-5)=3*4m-3*5=12m-15

4 0

3 years ago

-2 1/3 divided by -3/5

Aleonysh [2.5K]

Answer:

나는 대답이 글꼴 알고 있다고 생각한다.나는 대답이 글꼴 알고 있다고 생각한다.

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2 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

Which statement is true for the tables?

Flauer [41]

Answer:

Table A represents a function, but Table B does not represent a function.

Step-by-step explanation:

We have to select the correct option among the given 4 options after judging the given two tables attached to this question.

The first table shows that for each x values there is only one y value. Therefore, this is a function.

But in the second table shows that for each x value there are multiple y values since we are getting y = 1 and 2 for x = 5.

Hence, table B is not a function. it is just a relation. (Answer)

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3 years ago

How can you solve an equation like this 8x-17 by its self

nalin [4]

Step-by-step explanation:

This is an algebraic expression, not an equation

4 0

3 years ago