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devlian [24]
3 years ago
11

In Charles's law, gas volume is directly related to the Celsius temperature.

Chemistry
2 answers:
melamori03 [73]3 years ago
5 0
It’s true, gas is related to the calculus temp
kati45 [8]3 years ago
3 0
Yes this is true gas is related to the celcuis temp
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Which of the following types of rocks are likely to be formed due to compacting and cementing?
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Answer:

Sedimentary only

Explanation:

when compacting and cementing happens then a sedimentary rock can and is made!

hope this helps!

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2 years ago
Which option is an example of a physical property?
4vir4ik [10]
Physical property is C.Density
4 0
3 years ago
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Which of the following is false? a. an apoenzyme can catalyze its reaction without its cofactor b an organic cofactor can be cal
ozzi

Answer: Option (a) is the correct answer.

Explanation:

A protein part of an enzyme is known as an apoenzyme. An apoenzyme combines with a cofactor, it is known as holoenzyme.

Without a cofactor an apoenzyme cannot function as cofactor helps in the formation of an active enzyme system and provides a specific site on enzyme for the substrate.

Whereas a non-protein chemical compound or metal ion that helps in the activity of enzyme as a catalyst is known as a cofactor. A metal ion cofactor can be bound directly to the enzyme or to a coenzyme.

The organic non-protein molecules which bind to the protein molecule to form an active enzyme is known as a coenzyme. Coenzymes are small size molecules which help the enzymes to act as a catalyst.

Therefore, we can conclude that the statement an apoenzyme can catalyze its reaction without its cofactor, is false.

3 0
3 years ago
A fifth-grade science class puts half of a white tablet in a test tube with 10 milliliters (mL) of water at 21°C (70°F). The tab
hichkok12 [17]

Answer:

change in water tempreture.

Explanation:

5 0
2 years ago
A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83
guapka [62]

Answer:

a. 478.69 K

b. 939.43 cm^{3}

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

T_{o} = 400K

P_{o} = 125 Kpa =  125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 m^{3}⋅Pa⋅K^{-1}⋅mol^{-1}

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

83.8 = (0.03 × 35.5) (T_{1} - 400K)

83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

T_{1}  = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

V_{1}   = (785 × 478.69)/400

V_{1}   = 939.43 cm^{3}

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

6 0
3 years ago
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