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devlian [24]
3 years ago
11

In Charles's law, gas volume is directly related to the Celsius temperature.

Chemistry
2 answers:
melamori03 [73]3 years ago
5 0
It’s true, gas is related to the calculus temp
kati45 [8]3 years ago
3 0
Yes this is true gas is related to the celcuis temp
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Tristearin and stearic acid are insoluble in water. However, sodium stearate (soap) is soluble. Why is there this difference in
kupik [55]

Explanation:

Sodium stearate , is the soap , it a ionic compound , hence , can easily break to cation and anion , and therefore is soluble in water .It works on the principle of micelle formation .

Tristearin and stearic acid are fatty acids , and have are carboxyl group and have a very huge hydrocarbon chain , making it non polar in nature ,hence is is insoluble in water , since , water is a polar molecule .

7 0
3 years ago
You may have to recrystallize any or all of the components of your extraction mixture, benzoic acid, ethyl-4-aminobenzoate and f
hjlf

Answer:

the Recrystallization solvents are;

-Sodium Hydroxide Base (NaOH)

- Hydrochloric Acid (HCl)

- Sand bath when acidic and basic components are removed.

Explanation:

Recrystallization is simply a technique used to purify an impure compound in a solvent.

Now, we want to purify the mixture of benzoic acid, Ethyl-4-aminobenzoate and fluorenone.

For the benzoic acid, it can be separated out of the mixture by addition of sodium hydroxide base (NaOH).

The Ethyl - 4 - aminobenzoate will be separated from the mixture by the addition of Hydrochloric Acid (HCl).

The fluorenone would be separated out by heating the mixture in a sand bath after the basic and acidic components have already been extracted out.

Thus, the Recrystallization solvents are;

-Sodium Hydroxide Base (NaOH)

- Hydrochloric Acid (HCl)

- Sand bath when acidic and basic components are removed.

6 0
3 years ago
When comparing propionic acid (CH3CH2COOH) and sodium propionate (CH3CH2COONa), the one that is more soluble in water is When co
vova2212 [387]

Answer:

When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate.

When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose

When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid

Explanation:

When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate. Because always a salt is more soluble in water than its acid (Solubility of propionic acid is 0,37g/mL and of sodium propionate is 1g/mL).

When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose because cyclohexane is made from petroleum and its polarity is very low (cyclohexane is insoluble in water and solubility of glucose is 0,91g/mL).

When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid because an acid has a medium-high solubility in water but, again, an alkane derived from petroleum has very low solubility in water (hydrochloric acid has a solubility of 0,823g/mL and ethyl chloride is insoluble in water).

I hope it helps!

6 0
3 years ago
Calculate the molarity of the solution.
IRISSAK [1]
<span>The formula given for it is 
moles = given wt/mol.Wt

 Mol.wt of  nacl
nacl=23+35.5
=58.5 gm
 Moles = 29/58.5
= 0.495
~ 0.15 moles </span>
8 0
3 years ago
Read 2 more answers
When 5-bromo-2,2-dimethyl-1-pentanol is treated with sodium hydride, a compound with molecular formula c7h14o is obtained. choos
8090 [49]

Answer:

See attachment

Explanation:

See attachment

5 0
3 years ago
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