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3 years ago

How many grams are in 5.60 moles of sodium hydroxide (NaOH)

Chemistry

2 answers:

Illusion [34]3 years ago

8 0

Answer: I believe it should be 224g.

Explanation: There are 40g for every one mole of NaOH, so multiply the two to get to 224. I hope that helps!

Nostrana [21]3 years ago

5 0

Mass of NaOH = 223.983 g

<h3>Further explanation </h3>

A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) by the molar mass of an element or molecule

$\tt \boxed{\bold{n=\dfrac{mass}{MW}}}$

MW of NaOH = 39.997 g/mol

moles of NaOH= 5.6

Mass of NaOH :

$\tt mass=mol\times MW\\\\mass=5.6~moles\times 39,997 g/mol\\\\mass=223.983~g$

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4 years ago

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lara31 [8.8K]

Answer:

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Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

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0.66 = mass of hexane /10

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Next, we shall write the balanced equation for the reaction. This is given below:

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Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

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Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

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3 years ago

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Answer:

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3 years ago

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timama [110]

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91- 14 (1N) = 77 m/z

We are also told that there are carbon, hydrogens and oxygens present, so we will assume there is at least one oxygen which has a mass of 16 and subtract that value.

77 - 16 (1 O) = 61 m/z

Now we will try to get as close as possible to the remaining mass with carbons that has a mass of 12, and fill the remaining mass with hydrogens that have a mass of 1.

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The current formula would be C₅HON, but this structure is impossible since we do not have enough hydrogens to satisfy the carbons. So we can try to use 4 carbons instead and fill the rest with hydrogens.

4 x 12 = 48
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The current formula would be C₄H₁₃ON. The most hydrogens we can have in a compound is 2n+2 where n is the number of carbons. So with 4 carbons the most hydrogens we could have is 10. Therefore, our formula has too many hydrogens and also cannot work. So we cannot make up the remaining mass with carbons and hydrogens, therefore, we should add another oxygen before working with carbons and hydrogens.

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The current formula is now C₃H₉O₂N. To test if this formula works we can calculate the double bond equivalents (DBE), also known as degrees of unsaturation.
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leva [86]

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6 0

3 years ago

How many grams are in 5.60 moles of sodium hydroxide (NaOH)​

How many grams are in 5.60 moles of sodium hydroxide (NaOH)