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koban [17]
3 years ago
8

A fifth-grade science class puts half of a white tablet in a test tube with 10 milliliters (mL) of water at 21°C (70°F). The tab

let bubbles rapidly for three minutes until it is gone. Students record the final temperaturo at 20°C (637)
Which choice best identifies evidence that a chemical reaction occurred?
tablet was white
tablet broke in hall
tablet dissolved in the water
change in water temperature
Chemistry
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

change in water tempreture.

Explanation:

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True

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Waves move out through the ground from the source of an<br> earthquake.<br> True<br> ► False
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When hydrogen is combined with a metal, it has an oxidation number of _____.
solmaris [256]
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8 0
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Which of the following most completely describes an object's motion?
Gre4nikov [31]
Hello!

This is a difficultly easy question, mostly because it seems like all of the answers would be right, but if I had to choose one, I would say (D) because this option gives the most detail.

Option A only tells us how fast a car was moving
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Therefore, Option (D) is correct


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8 0
3 years ago
Read 2 more answers
At equilibrium, the concentrations in this system were found to be [N2]=[O2]=0.200 M and [NO]=0.600 M. N2(g)+O2(g)↽−−⇀2NO(g) If
cestrela7 [59]

Answer:

0.84M

Explanation:

Hello,

At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:

K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9

Now, the new equilibrium condition, taking into account the change x, becomes:

9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}

Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:

\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}

Thus, we arrange the equation as:

\frac{1}{9} (0.9-2x)^2=(0.2+x)^2\\0.09-0.4x+4x^2=0.04+0.4x+x^2\\3x^2-0.8x+0.05=0\\x_1=0.06

Finally, the new concentration is:

[NO]_{eq}=0.9-0.06=0.84M

Best regards.

7 0
3 years ago
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