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natulia [17]
3 years ago
13

Ptrpared a solution of sodium chloride (NaCl) by measuring out 49.Umol of sodium chloride into 150. ML. Volumetric flask and fil

ling the flask to the mark with water. Calucate the concentration in mol/L of the sodium chloride solution,
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

Data

Substance = NaCl

moles of NaCl = 49

volume = 150 ml

Process

Molarity is a unit of concentration that makes a relation of the moles of a substance and the volume.

Molarity = moles / volume (L)

1.- Convert 150 ml to L

                  1000 ml ------------------ 1 L

                     150 ml -----------------  x

                      x = (150 x 1) / 1000

                      x = 0.15 L

2.- Substitution

Molarity = 49 / 0.15

Molarity = 326. 7

I have a doubt if the number of moles is 49 moles or 49μmoles            

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<h3>Answer:</h3>

5.55 mol C₂H₅OH

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

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