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natulia [17]
3 years ago
13

Ptrpared a solution of sodium chloride (NaCl) by measuring out 49.Umol of sodium chloride into 150. ML. Volumetric flask and fil

ling the flask to the mark with water. Calucate the concentration in mol/L of the sodium chloride solution,
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

Data

Substance = NaCl

moles of NaCl = 49

volume = 150 ml

Process

Molarity is a unit of concentration that makes a relation of the moles of a substance and the volume.

Molarity = moles / volume (L)

1.- Convert 150 ml to L

                  1000 ml ------------------ 1 L

                     150 ml -----------------  x

                      x = (150 x 1) / 1000

                      x = 0.15 L

2.- Substitution

Molarity = 49 / 0.15

Molarity = 326. 7

I have a doubt if the number of moles is 49 moles or 49μmoles            

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The end point in a titration of a 58mL sample of aqueous HCl was reached by the addition of 25mL of 0.83MNaOH titrant. The react
Bess [88]

Answer:

0.36 M

Explanation:

Let's consider the following neutralization reaction.

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

25 mL of 0.83 M NaOH reacted. The moles of NaOH that reacted are:

0.025 L × 0.83 mol/L =0.021 mol

The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 0.021 moles.

0.021 moles are contained in 58 mL of HCl. The molar concentration of HCl is:

M = 0.021 mol/0.058 L

M = 0.36 M

4 0
3 years ago
HURRYYY!!!!<br> Convert 7.13 x 10^28 atoms of calcium (Ca) to moles of calcium.
puteri [66]

Answer:

<h2>118,438.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}\\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.13 \times  {10}^{28} }{6.02 \times  {10}^{23} }  \\  = 118438.538...

We have the final answer as

<h3>118,438.5 moles</h3>

Hope this helps you

4 0
3 years ago
How many moles of solute would be dissolved in .500 kg of solvent to make a 2.50 molal NaOH solution?
Tom [10]

Molality is a measure of concentration that relates the moles of solute to the kilograms of solvent, it is described by the following equation:

Molality=\frac{molSolute}{kgSolvent}

We are given the molality(2.50m) and kilograms of solvent(0.500kg), so we solve for moles of solute from the equation:

molSolute=Molality\times kgSolvent\begin{gathered} molSolute=2.50m\times0.500kg \\ molSolute=1.25molSolute \end{gathered}

To make a 2.50molal NaOH solution would be needed 1.25moles of solute

Answer: 1.25 moles

3 0
1 year ago
How many nucleons are in an Iodine element? Okay
Lady_Fox [76]

Answer:

there are 74

Explanation:

3 0
2 years ago
I have two solutions. In the first solution, 1.0 moles of sodium chloride is dissolved to make 1.0 liters of solution. In the se
charle [14.2K]

i not sure but I think yes

6 0
2 years ago
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