1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ludmilkaskok [199]
3 years ago
11

How is acceleration related to force when mass is constant, according to Newton's second law of motion?

Physics
2 answers:
kherson [118]3 years ago
5 0

Answer:

According to Newton's second law of motion, acceleration is directly proportional to force. As the force increases (when mass is constant), the acceleration increases. This can be shown in the following formula.

f = ma

a =  \frac{f}{m}

f = force

m = mass

a = acceleration

Bas_tet [7]3 years ago
5 0

Answer:

The force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration

You might be interested in
Why is it important for you to understand the basics of organ systems?
marissa [1.9K]
This question can have ALOT of answers but ill leave you with these summed up points and you can take what you need from it they are get right to the point! Sorry if they long paragraphs scare you lol




*You want to provide patients the best care possible. Most often your patients will have a disease. Diseases result when there is something abnormal in the anatomy and physiology of a structure. With a car, you can’t understand how to fix an engine if you don’t know how it works. The same is true with your patients. You can’t really understand how to treat them or why the treatment works, if you don’t understand how the effected body system normally functions.

*Patients will want to understand their diseases. In order to help them understand what is going wrong, you have to first understand how a particular organ is supposed to work. In addition, you will need to be able to explain these things to patients in a way that they can understand. If you don’t understand it well, you won’t be able to explain it. Your patient’s confidence in your ability will be at least partially determined by your ability to discuss what you are doing and why you are doing it. You will need to look up information if you are not sure.

*Organ systems are so interconnected that a disease in one system may result in a symptom in another system. Without seeing the normal interconnectedness, you cannot fully understand the disease.


*Success in an allied health field requires at least three things. First, you must have the personality to be able to support and help patients. Secondly, you must have the scientific and technical knowledge necessary to make the correct decisions regarding patient care. Thirdly, you must have the clinical skills necessary to implement this kno
5 0
3 years ago
How did the continental Shelf form? Please help, thank you!! :)
shutvik [7]
The movements of the tectonic plates
6 0
3 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.
Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

6 0
3 years ago
A 58.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 140 m/s from the top of a cliff
strojnjashka [21]

(a) 6.43\cdot 10^5 J

The total mechanical energy of the projectile at the beginning is the sum of the initial kinetic energy (K) and potential energy (U):

E=K+U

The initial kinetic energy is:

K=\frac{1}{2}mv^2

where m = 58.0 kg is the mass of the projectile and v=140 m/s is the initial speed. Substituting,

K=\frac{1}{2}(58 kg)(140 m/s)^2=5.68\cdot 10^5 J

The initial potential energy is given by

U=mgh

where g=9.8 m/s^2 is the gravitational acceleration and h=132 m is the height of the cliff. Substituting,

U=(58.0 kg)(9.8 m/s^2)(132 m)=7.5\cdot 10^4 J

So, the initial mechanical energy is

E=K+U=5.68\cdot 10^5 J+7.5\cdot 10^4 J=6.43\cdot 10^5 J

(b) -1.67 \cdot 10^5 J

We need to calculate the total mechanical energy of the projectile when it reaches its maximum height of y=336 m, where it is travelling at a speed of v=99.2 m/s.

The kinetic energy is

K=\frac{1}{2}(58 kg)(99.2 m/s)^2=2.85\cdot 10^5 J

while the potential energy is

U=(58.0 kg)(9.8 m/s^2)(336 m)=1.91\cdot 10^5 J

So, the mechanical energy is

E=K+U=2.85\cdot 10^5 J+1.91 \cdot 10^5 J=4.76\cdot 10^5 J

And the work done by friction is equal to the difference between the initial mechanical energy of the projectile, and the new mechanical energy:

W=E_f-E_i=4.76\cdot 10^5 J-6.43\cdot 10^5 J=-1.67 \cdot 10^5 J

And the work is negative because air friction is opposite to the direction of motion of the projectile.

(c) 88.1 m/s

The work done by air friction when the projectile goes down is one and a half times (which means 1.5 times) the work done when it is going up, so:

W=(1.5)(-1.67\cdot 10^5 J)=-2.51\cdot 10^5 J

When the projectile hits the ground, its potential energy is zero, because the heigth is zero: h=0, U=0. So, the projectile has only kinetic energy:

E = K

The final mechanical energy of the projectile will be the mechanical energy at the point of maximum height plus the work done by friction:

E_f = E_h + W=4.76\cdot 10^5 J +(-2.51\cdot 10^5 J)=2.25\cdot 10^5 J

And this is only kinetic energy:

E=K=\frac{1}{2}mv^2

So, we can solve to find the final speed:

v=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2(2.25\cdot 10^5 J)}{58 kg}}=88.1 m/s

4 0
3 years ago
Capacitor C1 is initially charged to V1 and capacitor C2 is initially charged to V2. The capacitors are then connected to each o
o-na [289]

Answer:

<em>20.08 Volts</em>

Explanation:

<u>Parallel Connection of Capacitors</u>

The voltage across any two elements connected in parallel is the same. If the elements are capacitors, then each voltage is

\displaystyle V_1=\frac{Q_1}{C_1}

\displaystyle V_2=\frac{Q_2}{C_2}

They are both the same after connecting them, thus

\displaystyle \frac{Q_2}{C_2}=\frac{Q_1}{C_1}

Or, equivalently

\displaystyle Q_2=\frac{C_2Q_1}{C_1}

The total charge of both capacitors is

\displaystyle Q_t=Q_1\left(1+\frac{C_2}{C_1}\right)

We can compute the total charge by using the initial conditions where both capacitors were disconnected:

Q_t=V_{10}C_1+V_{20}C_2=25\cdot 24+13\cdot 11=743\ \mu C

Now we compute Q1 from the equation above

\displaystyle Q_1=\frac{Q_t}{\left(1+\frac{C_2}{C_1}\right)}=\frac{743}{\left(1+\frac{13}{24}\right)}=481.95\ \mu C

The final voltage of any of the capacitors is

\displaystyle V_1=V_2=\frac{481.95}{24}=20.08\ V

7 0
2 years ago
Other questions:
  • Which type of galaxy is too small for gravity to form it into an easily describable shape?
    15·2 answers
  • A 1000-kg aircraft going 25 m/s collides with a 1500-kg aircraft that is parked. They stick
    5·1 answer
  • For a given velocity of projection in a projectile motion, the maximum horizontal distance is possible only at ө = 45°. Substant
    6·1 answer
  • NEED ANSWER ASAP
    6·2 answers
  • A 38.0 kg child is in a swing that is attached to ropes 1.70 m long. The acceleration of gravity is 9.81 m/s 2 . Find the gravit
    13·1 answer
  • Raising the temperature of a gas will increase its pressure if the volume of the gas
    7·1 answer
  • a stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes th
    7·1 answer
  • What is one characteristic of the organization of the Periodic Table?
    12·1 answer
  • A ball is dropped off a cliff and falls for 24 seconds. How far did the ball fall from the top down
    7·1 answer
  • The magnetic field 40.0 cm away from a long, straight wire carrying current 2.00 A is 1.00μT. (a) At what distance is it 0.100μ
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!