Why are many adults and youth in the United states overweight?

Physics

2 answers:

lbvjy [14]3 years ago

8 0

Answer:

There are different answers to that, like if you read a passage or something.

Explanation:

These days many people do not get exercise. A lot of jobs are now done indoors and do not require any physical activities. Technology is becoming more advanced and many people prefer using machines to do the heaving lifting.

There are a lot of fast-food restaurants and this is where a lot of people in the US choose to eat. The food is cheap and easy to pick up. This food is convenient for people on the go. The food is not healthy and it causes weight gain.

In the US, many young children find it cool to smoke. Smoking decreases the body's strength and it causes a decrease in physical health, causing people to gain weight.

Everyone has a phone these days, if not some kind of electronic device to chat with people or play games. Over time, playing on electronic devices replaces doing physical activities.

Anna11 [10]3 years ago

6 0

Answer:

I'd imagine fast food is a lot more popular than most countries over there and easier to get hold of.

Explanation:

america

You might be interested in

Explain what happens to the pitch of a cell phone ringing when the amplitude of a sound wave increases.

rewona [7]

As the amplitude of a sound wave increases the pitch of the ringing would be much higher (like if you were to inhale helium.. just with a phone)

3 0

3 years ago

Read 2 more answers

It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f

goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time ( $\Delta t$ )

$I=F \Delta t$

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

$I=(ma) \Delta t$

However, the acceleration is the ratio between the change in velocity ( $\Delta v$ ) and the contact time ( $\Delta t$ ): $a=\frac{\Delta v}{\Delta t}$ , so the previous equation becomes