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algol [13]
3 years ago
10

you showed me what true love is really like and made my confidence come back :) couldn't have asked for anything better!!

Physics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

lucky you cointinue

Explanation:

thxs for free points

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Why is alpha rays not suitable to scan baggage at the airport?​
Inga [223]

Answer:

Alpha particles are not used to check baggage in airport as these rays are not penetrated far through matter.

<u>Explanation: </u>

Alpha particles are produced by the <em>decay of a radioactive nucleus.</em> These alpha rays are <em>ceased by paper</em>. The <em>nucleus</em> of the helium atom is made up of <em>two protons and two neutrons</em> is the particle <em>ejected by alpha particle</em>.

As helium is <em>harmless and as an inert gas</em>, so these particles are not dangerous in themselves. The airport baggage security uses only X-ray scanners to inspect. These rays identify the <em>hidden items inside the baggage. </em>

4 0
3 years ago
What are political obstacles keeping wind turbine from being used?
erastova [34]

Explanation:

Turbines might cause noise and aesthetic pollution.

Although wind power plants have relatively little impact on the environment compared to conventional power plants, concern exists over the noise produced by the turbine blades and visual impacts to the landscape.

The inflexibility, variability, and relative unpredictability of wind power as a means for electricity production, are the most obvious barriers to an easy integration and widespread application of wind power." Thus, the uncertainty of the wind requires a system that is always available to replace all the electrical output created by the wind turbine system. In other words, it is too expensive to have wind turbines lying around that don't do anything.

7 0
3 years ago
A cyclist travelled 32 kilometers for both the 1st and 2nd hours. He took a 30 minute break to eat his lunch. He then travelled
Reika [66]

Answer:

The cyclist's average speed is 13.43 \frac{km}{h}

Explanation:

Speed ​​is a quantity that expresses the relationship between the space traveled by an object and the time used for it. That is, speed is the magnitude that expresses the variation in position of an object and as a function of time, which would be the same as saying that it is the distance traveled by an object in the unit of time.

Average speed relates the change in position to the time taken to effect that change:

speed=\frac{change in position}{time} =\frac{distance}{time}

In this case:

  • total distance traveled= 32 km + 15 km= 47 km
  • total time=  3 hours that the cyclist travels + 30 minutes of rest = 3 hours + 0.5 hours (being 60 minutes equal to 1 hour, then 30 minutes equals 0.5 hours) = 3.5 hours

Replacing:

speed=\frac{47 km}{3.5 h}

and solving, you get:

speed= 13.43 \frac{km}{h}

<u><em>The cyclist's average speed is 13.43 </em></u>\frac{km}{h}<u><em></em></u>

3 0
3 years ago
A beam of electrons moving in the x-direction enters a region where a uniform 208-G magnetic field points in the y-direction. Th
GREYUIT [131]

Answer:

1.26\cdot 10^7 m/s

Explanation:

When a charged particle moves perpendicularly to a magnetic field, the force it experiences is:

F=qvB

where

q is the charge

v is its velocity

B is the strength of the magnetic field

Moreover, the force acts in a direction perpendicular to the motion of the charge, so it acts as a centripetal force; therefore we can write:

qvB=m\frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the orbit of the particle

The equation can be re-arranges as

v=\frac{qBr}{m}

where in this problem we have:

q=1.6\cdot 10^{-19}C is the magnitude of the charge of the electron

B=208 G=208\cdot 10^{-4}T is the strength of the magnetic field

The beam penetrates 3.45 mm into the field region: therefore, this is the radius of the orbit,

r=3.45 mm = 3.45\cdot 10^{-3} m

m=9.11\cdot 10^{-31} kg is the mass of the electron

So, the electron's speed is

v=\frac{(1.6\cdot 10^{-19})(208\cdot 10^{-4})(3.45\cdot 10^{-3})}{9.11\cdot 10^{-31}}=1.26\cdot 10^7 m/s

6 0
3 years ago
1: Solve for acceleration. Write the units of your answer next to the number
aleksandrvk [35]
1. 7.1111m/s Recurring
Solution a = v/t basically divide the velocity by the time taken
2. 9.375m/s
Same solution as before
5 0
3 years ago
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