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Helen [10]
3 years ago
5

How is 1/2+1/4 solved differently than 1/2+1/3

Mathematics
1 answer:
MrRa [10]3 years ago
4 0
To solve 1/2+1/4 you only need to change the denominator of 1/2 to solve and for 1/2+1/3 you have to change the denominator of both fractions in order to solve. I think that’s what it’s asking
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Two mechanics worked on a car. The first mechanic charged S95 per hour, and the second mechanic charged $115 per hour.
natima [27]

Answer:

First mechanic worked for 10 hours and second mechanic worked for 15 hours.

Step-by-step explanation:

Let first mechanic worked for X hours and second mechanic worked for Y hours .

Now, according to the question , they worked for a total of 25 hours .

Thus ,

X + Y = 25.

Y = 25 - X   -(1)

Also, first mechanic is charging $ 95 per hour and second mechanic is charging $115 per hour .

Thus, total money charged by them will be 95X + 115Y .

Which is given to be $2675 in the question.

Thus 95X + 115Y = 2675.   -(2)

Putting equation 1 in equation 2 we get ,

95X + 2875 - 115X = 2675

20X = 200

X = 10 hours.

Thus , Y =  25 - X = 15 hours.

Thus first mechanic worked for 10 hours and second mechanic worked for 15 hours.

5 0
3 years ago
Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind
Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

  • The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

\displaystyle \frac{AB}{A'B'}  = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}

Which gives;

\displaystyle \frac{AB}{A'B'}  = \frac{AB}{2 \cdot AB} = \frac{1}{2}

A'B' = 2·AB

Therefore;

  • Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>

Learn more about dilation transformation here:

brainly.com/question/2458912

3 0
2 years ago
Finding the geometric mean
grigory [225]

Answer:

To find the geometric mean of two numbers, just find the product of those numbers and take the square root!

Step-by-step explanation:

4 0
2 years ago
Let f(x)=x+7 and g(x)=x-4 Find f(x) x g(x)
Sveta_85 [38]

Answer:

C. x²+3x-28

Step-by-step explanation:

f(x) = x +7

g(x) = x -4

f(x) · g(x) = (x-4)(x+7)

              = x²+7x-4x-28

              = x²+3x-28

3 0
3 years ago
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What is this pls help it tyler
Alisiya [41]

Answer:

13

Step-by-step explanation:

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