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vovangra [49]
3 years ago
11

You wish to find a 95% confidence interval for the mean number of times men change channels with a remote control during a comme

rcial. based on a preliminary study, you estimate σ = 15. how many commercials' worth of data do you need to have a margin of error no more than 3?
Mathematics
1 answer:
gogolik [260]3 years ago
4 0
For margin of error to be a maximum of 3:
3 = z*(SD / sqrt(n)), where z is the z-score, SD is the standard deviation and n is the sample size.
z = 1.96 for a 95% confidence interval, and we are given SD = 15.
3 = 1.96*15/sqrt(n)
sqrt(n) = 9.8
n = 96.04 ~ 96 commercials.

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Answer:

3:45

Step-by-step explanation:

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2 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
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Considering that the addresses of memory locations are specified in hexadecimal.

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b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

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=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

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∴ the range = 4095

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Learn more : brainly.com/question/18993173

6 0
2 years ago
A widget company produces 25 widgets a day,5 of which are defective.Find the probability of selecting 5 widgets from the 25 prod
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P = ( ⁵C₀ * ²⁰C₅) / ²⁰C₅

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=0.292 ..

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