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dybincka [34]
3 years ago
12

Solve for h ab - s - 2d - 3t = 4h ? = h

Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0
To get a single h, all you have to do is divide everything by 4
so h = \frac{ab -s -2d- 3t}{4}
You might be interested in
The degree of the function f(x) = -(x + 1)2(2x - 3)(x + 2)2 is<br> , and its y-intercept is
Serggg [28]

Answer:

Degree = 5

Y intercept = 12

Step-by-step explanation:

our function is given as

f(x)=-(x+1)^2 \cdot (2x-3) \cdot (x+2)^2

in the above polynomial our variable is x and it is being multiplied for 5 times. Hence the probable degree for the above polynomial is 5

In order to find the y intercept , we need to put x=0 in f(x) as y intercept is the point at which the function graphically meets y axis and where x = 0

Hence

f(0)=-(0+1)^2 \cdot (2(0)-3) \cdot (0+2)^2

f(0)=-(1)^2 \cdot (0-3) \cdot (2)^2

f(0)=-1 \cdot (-3) \cdot 4

f(0)=3 \cdot 4

f(0)=3 \times 4

f(0)=12

Hence the y intercept is 12 units

6 0
3 years ago
A 6 sided die was rolled 9 times. What is the mode of these rolls?
yuradex [85]
That 1,2,3,4,5,6 is one the die and it has a chance to at least get all the numbers at least once but u dont have enough data so i can help u more.
6 0
3 years ago
MNMNMNMNMMMNMNMNMNMNMNMMNMNMN
IrinaVladis [17]
All you have to do is divide each one by its other number.  For example, 5.60 for 8 is the same as one for 0.70.  We accomplish this by dividing the 5.60 by 8.
So...
0.70
0.80
0.90
0.75
The first choice is the lowest.
6 0
3 years ago
The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0
3 years ago
Please help me please help me
romanna [79]
2/3 * 2 = 4/6

4/6 + 1/6 = 5/6

1 - 5/6 = 1/6

750*6 = 4500

Hope this helps! :)
8 0
3 years ago
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