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AveGali [126]
4 years ago
10

Please help it is algebraic properties of limits!

Mathematics
1 answer:
Lyrx [107]4 years ago
8 0

Answer:

Hi, I'd be happy to help. Is there a photo you can attach of the problem you need help with?

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Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
4 years ago
What is this method called?????​
Serga [27]

Answer:

The algebraic method is a collection of several methods used to solve a pair of linear equations with two variables.

Step-by-step explanation:

8 0
3 years ago
Solve these simultaneous equations:
ivolga24 [154]

Answer:

1) We have the system:

5*x - 3*y = 15

4*x + 3*y = 6

To solve this, we first need to isolate one of the variables in one of the equations, let's isolate x in the first equation:

x = 15/5 + (3/5)*y = 3 + (3/5)*y

Now we can replace this in the other equation to get:

4*( 3 + (3/5)*y) + 3*y = 6

and solve this for y.

12 + (12/5)*y  + 3*y = 6

(12/5 + 3)*y = 6 - 12 = -6

(12/5 + 15/5)*y = -6

(27/5)*y = -6

y = -6*(5/27) = 1.11

Now we can replace this in the equation:

x = 3 + (3/5)*y

To get the value of x.

x = 3 + (3/5)*1.11 = 3.67

Then the solution of this system is the point (3.67, 1.11)

2) Now we have the system:

2*x + 5*y = 26

4*x + 3*y = 24

The solution method is the same as before:

x = 26/2 - (5/2)*y = 13 - (5/2)*y

Now we replace this in the other equation:

4*( 13 - (5/2)*y) + 3*y = 24

52 - 10*y + 3*y = 24

52 - 7*y = 24

52 - 24 = 7*y

28 = 7*y

28/7 = y

4 = y

now we replace this in the equatio:

x = 13 - (5/2)*y

x = 13 - (5/2)*4 = 13 - 10 = 3

The solution of this sytem is (3, 4)

3) Now we have the system:

3*x + 3*y = 39

2*x - 3*y = -2

first we isolate x in the first equation:

x = 39/3 - 3*y/3 = 13 - y

Now we can replace this in the other equation:

2*(13 - y) - 3*y = -2

26 - 2*y - 3*y = -2

26 - 5*y = -2

26 + 2 = 5*y

28 = 5*y

28/5 = y = 5.6

Now we can replace this in the equation:

x = 13 - y

To get the x-value

x = 13 - 5.6 = 7.4

Then the solution for this system is (7.4, 5.6)

4 0
3 years ago
Dylan made a fruit punch by combining different fruit juices. Pineapple juice made up 25% of the fruit punch. When Dylan made th
ArbitrLikvidat [17]

Answer:

48 oz

Step-by-step explanation:

25%

= 100/25

=4

4x12

=48

(Don't forget to give Brainliest if this was helpful)

8 0
3 years ago
Read 2 more answers
It's possible to create a regular tessellation with a regular pentagon.<br><br> A. True<br> B. False
Aleonysh [2.5K]

Your answer is B. False. This is because it is not possible to repeat the shape of a regular pentagon and have it tessellate.
I hope this helps!

4 0
3 years ago
Read 2 more answers
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