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Anna007 [38]
4 years ago
8

A ductile cast-iron bar is to support a load of 178 kN in a heat-treating furnace used to make malleable cast iron. The bar is l

ocated in a spot that is continuously exposed to 500°C. Design the bar so that it can operate for at least 10 years without failing.

Physics
1 answer:
Nitella [24]4 years ago
3 0

Answer: L.M = 34.69

Area of the bar = 25835m^2

Explanation: To design a bar that can withstand temperature at 773K for 10years, we need to calculate and know:

1) the Larson Miller value

2) rupture time

3) creep rate

4) stress and load.

Please find the attached file for the solution

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Lucia is playing with magnetic toy vehicles. She has two identical toy vehicles (purple and pink) that start on opposite sides o
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Answer: The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet.

Explanation:

Brainliest

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3 years ago
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The period T of a simple pendulum is expressed by: √ where ‘l' is the length of the pendulum and ‘g' is the acceleration due to
OlgaM077 [116]

Answer:

T = T

Explanation:

The period of a simple pendulum is given by the formula

                           t = 2\pi \sqrt{\frac{l}{g} }

Where

                         l - length of the pendulum

                         g - acceleration due to gravity

The dimension of the physical quantities are given by,

                                   t  - T

                                   l - L

                                   g - m/s² - LT⁻²

Substituting in the above equation,

                                T = 2π √(L / LT⁻²)

Considering only the dimensional units in the equation

                                 T = √(L / LT⁻²)

                                  T = T

This shows that the formula for a simple pendulum is dimensionally consistent, T = T

3 0
3 years ago
Which of these is transparent?
jolli1 [7]
The answer is definitely A. A transparent material is a material that allows light to pass through it and can be seen through. A glass jar can be seen through. Some people might say B, which is a mirror, but a mirror cannot be seen through, it only shows reflection. Hope i helped. Have a nice day and Happy New Year.
3 0
3 years ago
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A circular loop of wire with area A lies in the xy-plane. As viewed along the z-axis looking in the −z-direction toward the orig
Sedaia [141]

Answer:

A) μ^ = - IA•k

B) Bx = 2D/IA

C) By = 4D/IA

D) Bz= -14D/(IA)

Step-by-step explanation:

We are given;

Torque; τ = D(2i^ − 4j^) Nm

Potential energy; U =− μ•B

Magnitude of magnetic field;

Bo = 15D/IA

a. The vector magnetic moment of the current loop is given as

μ^ = - μ•k

μ^ = -IA •k

b. Now, let's find the component of the magnetic field B.

If we assume B = Bx•i + By•j + Bz•k

Then, torque is given as

τ = μ^ ×B

τ = - IA •k × (Bx•i + By•j + Bz•k)

Note that;

i×i=j×j×k×k=0

i×j=k. j×i=-k

j×k=i. k×j=-i

k×i=j. i×k=-j

Then,

τ = - IA •k × (Bx •i + By •j + Bz •k)

τ= -IABx•(k×i) - IABy•(k×j) - IABz•(k×k)

τ= -IABx•j + IABy•i

τ= IABy•i - IABx•j

The given torque is τ = D(2i^ − 4j^)

Comparing coefficients;

Then,

-IABx = -4D

Bx = -4D/-IA

Bx = 4D/IA

c. Also,

IABy = 2D

Then, By= 2D/IA

d. To get Bz, let's use the magnitude of magnetic field Bo

Bo² = Bx² + By² + Bz²

(15D/IA)²=(4D/IA)²+(2D/IA)² + Bz²

Bz² = (15D/IA)²- (4D/IA)²- (2D/IA)²

Bz² = 225D²/(I²A²) - 16D²/(I²A²) - 4D²/(I²A²)

Bz² = (225D² - 16D²- 4D²)/I²A²

Bz² = 205D²/I²A²

Bz = √(205D²/(I²A²))

Bz = ± 14D/(IA)

So we want to determine if Bz is positive or negative

From the electric potential,

U=− μ•B

U= -(- IA k•(Bx i+By j+Bz k)

Note, -×- = +, i.i=j.j=k.k=1

i.j=j.k=k.i=0

Then,

U= IA k•(Bx i+By j+Bz k)

U = IABz

Since we are told that U is negative, then this implies that Bz is negative

Then, Bz= -14D/(IA)

7 0
3 years ago
When Mendeleev organized elements in his periodic table in order of increasing mass, similar elements with similar properties we
Temka [501]
Similar elements with similar properties were in the same groups and periods for instance lithium(Li) and sodium(Na) are alkaline metals and so belong to the same group (that is group 1).Also Hydrogen(H) and Helium(He) both have only one shell or energy level and so belong to the same period.
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