All categories

3 years ago

Which of these is transparent?

Physics

2 answers:

forsale [732]3 years ago

8 0

A. a glass jar. obvious.

jolli1 [7]3 years ago

3 0

The answer is definitely A. A transparent material is a material that allows light to pass through it and can be seen through. A glass jar can be seen through. Some people might say B, which is a mirror, but a mirror cannot be seen through, it only shows reflection. Hope i helped. Have a nice day and Happy New Year.

You might be interested in

A capacitor is formed from two concentric spherical conducting shells separated by vacuum. The inner sphere has radius 10.5 cm,

Step2247 [10]

Answer:

$U = 2.91 *10^{-5} J$

Explanation:

energy density can be obtained as

$U = \frac{1}{2}\epsilon_o E^{2}$

Where,

E is electric field $= \frac{kQ}{R^{2}}$

K COLOUMB CONSTANT =8.99*10^{9} N -m2 /C2

Q is charge = CV

C is capacitance = $4\pi \epsilon_o \frac{r_1 r_2}{r_2 -r_1}$

$=4\pi *8.85*10^{-12} [\frac{10.5*16.5}{16.5 -10.5}]$

$= 3.21*10^{-9} F$

$Q = 3.21*10^{-9} *150 = 4.81*10^{-7] C$

for r = 10.6 cm

$E = \frac{8.99*10^{9}*3.21*10^{-9}}{0.106^{2}}$

E = 2568.34 N/C

$U = \frac{1}{2}\epsilon_oE^{2}$

$U = \frac{1}{2}*8.85*10^{-12} *2568.34 ^2$

$U = 2.91 *10^{-5} J$

8 0

3 years ago

Why are common measurement systems important

kenny6666 [7]

So that international people don't mistake units for others. ex 1 inch could be mistaken for 1 cm in non American countries

6 0

3 years ago

An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, s

max2010maxim [7]

Answer:

xmax = 9.5cm

Explanation:

In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.

In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

$F_e=qE=ma$ (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

$a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}$

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

$x_{max}=v_o\sqrt{\frac{2d}{a}}$ (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

$x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm$

The horizontal distance traveled by the electron is 9.5cm

4 0

4 years ago

Two long, parallel wires are attracted to each other by a force per unit length of 305 µN/m. One wire carries a current of 25.0

kykrilka [37]

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

$\frac{F}{L} = \frac{kl_1l_2}{d}$