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4 years ago

As concentration increases by a tenth,what happens to the pH?

2 answers:

5 0

As the concentration of a solution, will increase by a tenth, the hydrogen ion concentration can become basic. The hydrogen ion concentration measures how acidic or basic the substance is, wherever zero is that the most acidic because of increase in H+ during a concentration, fourteen is that the most simple as a result of low H+ concentration and seven is taken into account neutral with an equal range<span> of H+ and OH- ions.

Explanation:
</span>
pH may be a measure<span> of the hydrogen </span>particle<span> concentration of </span>a solution<span>. Solutions with a high concentration of </span>atomic number 1<span>ions have </span>an occasional hydrogen ion concentration<span> and solutions with </span>occasional<span> concentrations of H+ ions have a high </span>hydrogen ion concentration.

<span>For a neutral </span>solution, pH=7
Acidic solutions <span>pH<7 </span>
Basic solutions have <span>pH>7</span>

The lowers the pH, a lot of<span> acidic </span>the solution and therefore the<span> higher the concentration of H+.</span>

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charle [14.2K]4 years ago

4 0

As concentration of a solution, increases by a tenth, the pH will become basic. The pH scale measures how acidic or basic the substance is, where 0 is the most acidic due to increase in H+ in a concentration, 14 is the most basic because of low H+ concentration and 7 is considered neutral with equal number of H+ and OH- ions.

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If a park is 5 miles away what is the average speed you have to maintain to arrive in 15 minutes

Nikolay [14]

Answer:

3 miles per hour

Explanation:

15 divided by 5 = 3

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4 years ago

When an electron enters a region of uniform magnetic field (B=0.19T), with its

kobusy [5.1K]

The radius of the track in the circular motion is 0.164 mm.

<h3>Magnetic force of the of charge</h3>

The magnetic force of the charge is calculated as follows;

F = qvB

<h3>Centripetal force of the charge</h3>

The centripetal force experienced by the charge is calculated as follows;

$F = \frac{mv^2}{r}$

<h3>The magnetic force is equal to the centripetal force</h3>

$qvB = \frac{mv^2}{r} \\\\qB = \frac{mv}{r} \\\\r = \frac{mv}{qB} \\\\$

<h3>The radius of the track</h3>

The radius of the track is calculated as follows;

$r = \frac{9.1 \times 10^{-31} \times 5.5 \times 10^6}{1.6 \times 10^{-19} \times 0.19} \\\\r = 1.64 \times 10^{-4} \ m\\\\r = 0.164 \times 10^{-3} \ m\\\\r = 0.164 \ mm$

Thus, the radius of the track in the circular motion is 0.164 mm.

Learn more about magnetic force here: brainly.com/question/13277365

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3 years ago

Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a larg

valentina_108 [34]

Answer:

-time it takes for the sled to come to a stop after launch of rocket = 7.244 s

-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m

Explanation:

From the question, looking at the motion while accelerating, we have;

Initial velocity; u = 0 m/s

Acceleration; a = 13.5 m/s²

Time; t = 3.3 s

Let's use first equation of motion to find final velocity (v).

v = u + at

v = 0 + (13.5 × 3.3)

v = 44.55 m/s

In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.

d1 = ut + ½at²

d1 = 0(3.3) + ½(13.5 × 3.3²)

d1 = 73.5075 m

Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².

Thus, from v = u + at, we can find the time it take for the sled to come to a stop.

Now, since it's coming to rest acceleration will be negative. Thus;

0 = 44.55 + (-6.15t)

0 = 44.55 - 6.15t

t = 44.55/6.15

t = 7.244 s

Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.

Thus, we'll use the equation;

v² = u² + 2as

Where s will be the second displacement which we will call d2.

Thus;

0² = 44.55² + (-2 × 6.15 × s)

0 = 1984.7025 - 12.3s

12.3s = 1984.7025

s = 1984.7025/12.3

s = 161.358

Thus, d2 = s = 161.358 m

Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;

= d1 + d2 = 73.5075 + 161.358 = 234.8655 m

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4 years ago

A lady walks 10 m to the north, then she turns and continues walking 30 m due east.

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Answer:

The distance covered is 40 m and the displacement is 31,6m.

Explanation:

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3 years ago

A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du

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Answer:

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