The complete question is missing, so i have attached the complete question.
Answer:
A) FBD is attached.
B) The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Explanation:
A) I've attached the image of the free body diagram.
B) The formula for the net force is given as;
F_net = mv²/r
We know that angular velocity;ω = v/r
Thus;
F_net = mω²r
Now, the minimum downward force is the weight and so;
mg = m(ω_min)²r
m will cancel out to give;
g = (ω_min)²r
(ω_min)² = g/r
ω_min = √(g/r)
The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Answer:
Mass of the other object is 38.45 kg.
Explanation:
Given:
The gravitational force between two objects is, N
Mass of one object is,
Distance between the objects is,
Gravitational constant is,
Let the mass of the other object be
Gravitational force is given as:
Plug in the given values and solve for . This gives,
Therefore, the mass of the other object is 38.45 kg.
Answer:
(A)
Explanation:
Given:
Charge of one particle (q₁) = -0.0050 C
Charge of another particle (q₂) = 0.0050 C
Separation between them (d) = 0.025 m
We know that, from Coulomb's law, electric force acting between two charged particles is given as:
Plug in the given values and solve for electric force, . This gives,
Therefore, option (A) is correct. Negative sign implies that the nature of electric force is attraction.