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Alenkinab [10]
2 years ago
8

How quickly would the 50kg box accelerate if the person applied a 570N force?

Physics
1 answer:
belka [17]2 years ago
6 0
Acceleration = force / mass = 570 / 50 = .... m/s^2
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2 years ago
If a person believes that dreams have hidden meaning he or she would agree with Freud's ideas about _ content
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A.lucid because it makes more sense yo the answer how about you do it yourself
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3 years ago
Elaborate on the classification of aluminum. A) Aluminum is a noble gas and has a full valence electron shell, is chemically non
scZoUnD [109]
The correct option is (B) <span>Aluminum is a metal and is shiny, malleable, ductile, conducts heat and electricity, forms basic oxides, and forms cations in aqueous solution.

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4 0
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Read 2 more answers
A square coil ℓ = 2cm on a side with 30 turns rotates in a uniform magnetic field, B~ = B0zˆ = 0.1Tˆz, such that the normal of t
kow [346]

Answer:

a) 1.2*10^{-3}cos(1.25t)

b) 0.49mV

Explanation:

a) The coil rotates periodically with period T. Hence, we can write the variation of the magnetic flux with a sinusoidal function, and with max flux NAB. Thus, we have that:

\Phi_B(t)=NABcos(\omega t)\\\\\omega=\frac{2\pi}{T}=1.25\frac{rad}{s}\\\\A=l^2=(0.02m)^2=4*10^{-4}m^2\\\\B=0.1T\\\\\Phi_B(t)=1.2*10^{-3}cos(1.25 t) W

where we have used the values given by the information of the problem for N B and A.

b)

the emf is given by:

emf=-\frac{d\Phi_B}{dt}=-NBA\omega sin(\omega t)\\\\emf(t=12.5s)=-(30)(0.1T)(4*10^{-4})(1.25\frac{rad}{s})sin(1.25*12.5)=1.49*10^{-4}V=0.49mV

hope this helps!!

5 0
3 years ago
An AC source is connected to a series combination of a light bulb and a variable capacitor. If the capacitance is increased, the
notsponge [240]

Answer:

Increases

Explanation:

Since power P=IV

Then it means when current increases, the power increases hence brightness increases. I represent current, P is power and v is voltage.

Current of capacitor when in series connection is given by

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where I is current across capacitor, f is frequency, C is capacitance and v is voltage across capacitance. From this second formula, it is evident that an increase in capacitance increases the current across the capacitor. Therefore, if current increases, power also increases leading to an increase in brightness

3 0
3 years ago
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