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3 years ago

How quickly would the 50kg box accelerate if the person applied a 570N force?

Physics

1 answer:

belka [17]3 years ago

6 0

Acceleration = force / mass = 570 / 50 = .... m/s^2

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A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Accelerati

slega [8]

Answer:

29223.6J

Explanation:

Given parameters:

Mass of Piano = 852kg

Height of lifting = 3.5m

Unknown:

Gravitational potential energy = ?

Solution:

The gravitational potential energy of a body can be expressed as the energy due to the position of a body;

G.P.E = mgh

m is the mass

g is the acceleration due to gravity

h is the height

Now insert the given parameters and solve;

G.P.E = 852 x 9.8 x 3.5 = 29223.6J

6 0

3 years ago

What is the shape of the trajectory that a charged particle follows in a uniform magnetic field?

Darya [45]

Answer:

circle

Explanation:

5 0

3 years ago

Which type of wave would not be classified as a transverse wave?

Jlenok [28]

Longitud wave something like that.

6 0

3 years ago

A solid sphere is released from the top of a ramp that is at a height h1 = 2.30 m. It rolls down the ramp without slipping. The

Oksi-84 [34.3K]

Answer:

The horizontal distance d does the ball travel before landing is 1.72 m.

Explanation:

Given that,

Height of ramp $h_{1}=2.30\ m$

Height of bottom of ramp $h_{2}=1.69\ m$

Diameter = 0.17 m

Suppose we need to calculate the horizontal distance d does the ball travel before landing?

We need to calculate the time

Using equation of motion

$h_{2}=ut+\dfrac{1}{2}gt^2$

$t=\sqrt{\dfrac{2h_{2}}{g}}$

$t=\sqrt{\dfrac{2\times1.69}{9.8}}$

$t=0.587\ sec$

We need to calculate the velocity of the ball

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2$

$K.E=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times(\dfrac{2}{5}mr^2)\times(\dfrac{v}{r})^2$

$K.E=\dfrac{7}{10}mv^2$

Using conservation of energy

$K.E=mg(h_{1}-h_{2})$

$\dfrac{7}{10}mv^2=mg(h_{1}-h_{2})$

$v^2=\dfrac{10}{7}\times g(h_{1}-h_{2})$

Put the value into the formula

$v=\sqrt{\dfrac{10\times9.8\times(2.30-1.69)}{7}}$

$v=2.922\ m/s$

We need to calculate the horizontal distance d does the ball travel before landing

Using formula of distance

$d =vt$

Where. d = distance

t = time

v = velocity

Put the value into the formula

$d=2.922\times 0.587$

$d=1.72\ m$

Hence, The horizontal distance d does the ball travel before landing is 1.72 m.

8 0

3 years ago

WDYK? Can you remember how ionic bonds were defined from your physical science class?

Stells [14]

Yes, ionic bond is formed by the transfer of electrons from and an atom of metallic element to the atom of an non metallic element

5 0

2 years ago