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sveticcg [70]
3 years ago
15

What is the greatest common factor of 48 and 64?

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

The GCF of 48 and 64 is 16

Step-by-step explanation:

To figure out GCF, you make a list of all the prime factors, pick out the numbers they have in common, and multiply them together.  In this case:

48:  2 x 2 x 2 x 2 x 3

64: 2 x 2 x 2 x 2 x 2 x 2

They have four 2's in common, so you multiply 2 x 2 x 2 x 2 =16

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P = √mx_ £x MX t make x the subject
vladimir2022 [97]

So, making x subject of the formula, x = [m - 2pt³ ±√(m²  - 4pt²m)]/{2t⁵}

<h3>How to make x subject of the formula?</h3>

Since p = √(mx/t) - t²x

So, p + t²x = √(mx/t)

Squaring both sides, we have

(p + t²x)² = [√(mx/t)]²

p² + 2pt²x + t⁴x² = mx/t

Multiplying through by t,we have

(p² + 2pt²x + t⁴x²)t = mx/t × t

p²t + 2pt³x + t⁵x² = mx

p²t + 2pt³x + t⁵x² - mx = 0

t⁵x² + 2pt³x - mx + p²t = 0

t⁵x² + (2pt³ - m)x + p²t = 0

Using the quadratic formula, we find x.

x = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}

where

  • a = t⁵,
  • b = (2pt³ - m) and
  • c =  p²t

Substituting the values of the variables into the equation, we have

x = \frac{-(2pt^{3} - m) +/-\sqrt{(2pt^{3} - m)^{2} - 4(t^{5})(p^{2}t) } }{2t^{5} }\\= \frac{-(2pt^{3} - m) +/-\sqrt{4p^{2} t^{6} - 4pt^{2}m + m^{2} - 4p^{2}t^{6} } }{2t^{5}}\\= \frac{-(2pt^{3} - m) +/-\sqrt{m^{2}  - 4pt^{2}m } }{2t^{5}}\\= \frac{m - 2pt^{3}  +/-\sqrt{m^{2}  - 4pt^{2}m } }{2t^{5}}

So, making x subject of the formula,  x = \frac{m - 2pt^{3} +/-\sqrt{m^{2}  - 4pt^{2}m } }{2t^{5}}

Learn more about subject of formula here:

brainly.com/question/25334090

#SPJ1

6 0
1 year ago
If a area of a rectangle is 24,396 centimeters and if width is 38 centimeters what is length?
Arisa [49]
Divide 24,396 by the width which is 38. It ends up being 642 cm. that is the length
4 0
3 years ago
Multiply<br><br> Which one ??? Please help
vladimir1956 [14]

Answer:

The 3rd one again

Step-by-step explanation:

(a+−2)(8a^{2}+−5a+3)

=(a)(8a^{2})+(a)(−5a)+(a)(3)+(−2)(8a^{2})+(−2)(−5a)+(−2)(3)

=8a^{3}−5a^{2}+3a−16a^{2}+10a−6

=8a^{3}−21a^{2}+13a−6

hope this helped:)

7 0
3 years ago
Which ordered pair lines on the x-axis? A(-1,2) B(1,-2) C(0,2) D(-1,0)
Afina-wow [57]

Answer:

D (-1,0). Only point D lies on the x-axis when graphed.

8 0
3 years ago
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PLEASE HELP !! ILL GIVE BRAINLIEST !!
Nady [450]

Answer:

<QPS and <TSU

4 0
3 years ago
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