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3 years ago

Systems of equations that has two points (-10,6)

Mathematics

1 answer:

mash [69]3 years ago

4 0

figuer this out -10-6= your answer

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<img src="https://tex.z-dn.net/?f=f%20%3D%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B4%7D%20" id="TexFormula1" title="f =(x) = \frac{x}{4}

Inga [223]

Answer:

g(x) = $\frac{x+3}{x-3}$

Step-by-step explanation:

From the picture attached,

Given function is,

f(x) = x + 1

We have to find the value of g(x) if the composite function has been given as,

f[g(x)] = g(x) + 1 = $\frac{2x}{(x-3)}$

g(x) = $\frac{2x}{(x-3)}-1$

= $\frac{2x-(x-3)}{(x-3)}$

= $\frac{(x+3)}{(x-3)}$

Therefore, g(x) = $\frac{x+3}{x-3}$ will be the answer.

5 0

2 years ago

Is 16to 14 and 64to60 equivalent

stiks02 [169]

NO. They are not.

We can prove this by turning those numbers into fractions:

16 / 14 = 1.1428 ; 64 / 60 = 1.0667

Or simply:

64 / 16 = 4
60 / 14 = 4.29

To get the equivalent of 16 to 14; we must multiply both numbers by 4.

16 * 4 = 64
14 * 4 = 56

The equivalent of 16 to 14 is 64 to 56.

3 0

3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago

What is 18.390 centimeters converted to millimeters

bogdanovich [222]

183.9 millimeters is the answer

7 0

3 years ago

Read 2 more answers

Solve the given system, using the substitution method.

alexandr1967 [171]

Y = 3x - 7 . . . . . (1)
6x - 2y = 12 . . . (2)

Putting (1) into (2) gives
6x - 2(3x - 7) = 12
6x - 6x + 14 = 12
14 = 12

Therefore, there is no solution.

5 0

2 years ago

Read 2 more answers