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Olin [163]
3 years ago
11

Systems of equations that has two points (-10,6)

Mathematics
1 answer:
mash [69]3 years ago
4 0

figuer this out -10-6= your answer

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<img src="https://tex.z-dn.net/?f=f%20%3D%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B4%7D%20" id="TexFormula1" title="f =(x) = \frac{x}{4}
Inga [223]

Answer:

g(x) = \frac{x+3}{x-3}

Step-by-step explanation:

From the picture attached,

Given function is,

f(x) = x + 1

We have to find the value of g(x) if the composite function has been given as,

f[g(x)] = g(x) + 1 = \frac{2x}{(x-3)}

g(x) = \frac{2x}{(x-3)}-1

      = \frac{2x-(x-3)}{(x-3)}

      = \frac{(x+3)}{(x-3)}

Therefore, g(x) = \frac{x+3}{x-3} will be the answer.

5 0
2 years ago
Is 16to 14 and 64to60 equivalent
stiks02 [169]
NO. They are not.

We can prove this by turning those numbers into fractions:

16 / 14 = 1.1428  ;  64 / 60 = 1.0667

Or simply:

64 / 16 = 4
60 / 14 = 4.29

To get the equivalent of 16 to 14; we must multiply both numbers by 4.

16 * 4 = 64
14 * 4 = 56

The equivalent of 16 to 14 is 64 to 56.

3 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
2 years ago
What is 18.390 centimeters converted to millimeters
bogdanovich [222]
183.9 millimeters is the answer
7 0
3 years ago
Read 2 more answers
Solve the given system, using the substitution method.
alexandr1967 [171]
Y = 3x - 7 . . . . . (1)
6x - 2y = 12 . . . (2)

Putting (1) into (2) gives
6x - 2(3x - 7) = 12
6x - 6x + 14 = 12
14 = 12

Therefore, there is no solution.
5 0
2 years ago
Read 2 more answers
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