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3 years ago

9

Consider a uniform hoop of radius r and mass m rolling without slipping. which is larger, its translational kinetic energy or it

s rotational kinetic energy?

1 answer:

OlgaM077 [116]3 years ago

3 0

<span>translational kinetic energy is larger than its rotational kinetic energy</span>

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When an earthquake occurs, energy radiates in all directions from its source. the source is also referred to as the ________?

vesna_86 [32]

Hypocenter (under the ground where earthquake actually begins), or epicenter(above hypocenter on the ground, useful to locate on the map)

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3 years ago

Read 2 more answers

A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.070

likoan [24]

Given Information:

length of slender rod = L = 90 cm = 0.90 m

mass of slender rod = m = 0.120 kg

mass of sphere welded to one end = m₁ = 0.0200 kg

mass of sphere welded to another end = m₂ = 0.0700 kg (typing error in the question it must be 0.0500 kg as given at the end of the question)

Required Information:

Linear speed of the 0.0500 kg sphere = v = ?

Answer:

Linear speed of the 0.0500 kg sphere = 1.55 m/s

Explanation:

The velocity of the sphere can by calculated using

ΔKE = ½Iω²

Where I is the moment of inertia of the whole setup ω is the speed and ΔKE is the change in kinetic energy

The moment of inertia of a rigid rod about center is given by

I = (1/12)mL²

The moment of inertia due to m₁ and m₂ is

I = (m₁+m₂)(L/2)²

L/2 means that the spheres are welded at both ends of slender rod whose length is L.

The overall moment of inertia becomes

I = (1/12)mL² + (m₁+m₂)(L/2)²

I = (1/12)0.120*(0.90)² + (0.0200+0.0500)(0.90/2)²

I = 0.0081 + 0.01417

I = 0.02227 kg.m²

The change in the potential energy is given by

ΔPE = m₁gh₁ + m₂gh₂

Where h₁ and h₂ are half of the length of slender rod

L/2 = 0.90/2 = 0.45 m

ΔPE = 0.0200*9.8*0.45 + 0.0500*9.8*-0.45

The negative sign is due to the fact that that m₂ is heavy and it would fall and the other sphere m₁ is lighter and it would will rise.

ΔPE = -0.1323 J

This potential energy is then converted into kinetic energy therefore,

ΔKE = ½Iω²

0.1323 = ½(0.02227)ω²

ω² = (2*0.1323)/0.02227

ω = √(2*0.1323)/0.02227

ω = 3.45 rad/s

The linear speed is

v = (L/2)ω

v = (0.90/2)*3.45

v = 1.55 m/s

Therefore, the linear speed of the 0.0500 kg sphere as its passes through its lowest point is 1.55 m/s.

8 0

3 years ago

¿Por qué es útil comprender tu condición física?

finlep [7]

Answer:

Es útil porque al saberlo evitas sobrexponerte a problemas como <em><u>enfermedades, desgarros o daños a largo plazo de tu cuerpo.</u></em>

Explanation:

When a person decides to start exercising or some type of physical activity, it is necessary for him to know how much his body can resist that activity during a defined period of time.

If in some way or another your body does not resist physical activity, you can hurt yourself, tear a ligament or muscle or get sick.

One of the most common diseases that almost nobody notices is the increase in circulatory and heart problems.

It is best to know your physical condition, how much weight you can carry with weights, or how long you can last doing physical activities.

4 0

3 years ago

A player kicks a soccer ball in a high arc toward the opponent's goal. When the soccer ball reaches its maximum height, how does

Artyom0805 [142]

Answer:

The speed of the soccer ball at height point is less than its initial speed

Explanation:

The initial velocity of the soccer can be written in vector form as

$v_{i$ = v cos θ î + v sin θ j

where $v_{i$ is initial velocity of the ball

v is the initial speed of the ball

Assume soccer ball is kicked at an angle θ with an horizontal and initial speed vm/s. Its horizontal component will be as,

$v_{x}$ = v cos θ

$v_{y}$ = v sin θ

At the maximum height, the vertical component becomes zero. therefore, the velocity of the soccer at the maximum point can be written as,

$v_{m}$ = v cos θ j

where, $v_{m}$ is velocity of the soccer ball at maximum height

5 0

4 years ago

dos contenedores de objetos tienen 30 y 40 kg de masa respectivamente y están sobre una superficie horizontal sin rozamiento una

Dmitry_Shevchenko [17]

Answer:

The acceleration of each mass is the same, and approximately equal to $1.43\,\,\frac{m}{s^2}$

Explanation:

Notice that the mass of the whole system is: 30 kg + 40 kg = 70 kg

If we use a net force of 100 N on the combined system, we can find the acceleration imparted to the masses via Newton's second law:

$F_{net}= M\,*\,a\\100\,\,N = 70\,\,kg * a\\a = \frac{100}{70} \,\frac{m}{s^2} \\a\approx 1.43\,\frac{m}{s^2}$

4 0

3 years ago