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jolli1 [7]
1 year ago
15

At the distance of Jupiter (6 times further away from the Sun than Earth) the amount of sunlight received per square centimeter

is different by what factor
Physics
1 answer:
givi [52]1 year ago
8 0

The amount of sunlight received per square centimeter is different by 36 times less.

<h3>What is the speed of light?</h3>

A fundamental physical constant, typically abbreviated as c, the speed of light in a vacuum is significant in many branches of physics. 299792458 metres per second, or around 300000 kilometres per hour or 186,000 miles per hour, is the precise figure. The special theory of relativity states that the maximum speed at which ordinary matter, energy, or any signal containing information may move across space is given by the constant c.

Visible light is an example of electromagnetic radiation that moves at the speed of light. Light and other electromagnetic waves appear to move instantly for many practical uses, but their limited speed has dramatic implications over vast distances and particularly sensitive measurements. The starlight that can be seen from Earth has been out there for a very long time, allowing people to see far-off objects and learn about the evolution of the cosmos. It can take minutes to hours for signals to reach from Earth to a spacecraft when corresponding with far-off space missions. The absolute shortest communication latency between computers, to computer memory, and within a CPU is fixed in computing at the speed of light.

to learn more about speed of light go to - brainly.com/question/104425

#SPJ4

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Explain the immediate impact of a catastrophic event
exis [7]
Any event<span> or force of nature that has </span>catastrophic consequences<span>, such as avalanche, earthquake, flood, forest fire, hurricane, lightning, tornado, tsunami and </span>
7 0
3 years ago
Sound enters the ear, travels through the auditory canal, and reaches the eardrum. The auditory canal is approximately a tube op
Juliette [100K]

Answer:

The fundamental frequency of can is 2.7 kHz.                          

Explanation:

Given that,

A typical length for the auditory canal in an adult is about 3.1 cm, l = 3.1 cm

The speed of sound is, v = 336 m/s

We need to find the fundamental frequency of the canal. For a tube open at only one end, the fundamental frequency is given by :

f=\dfrac{v}{4l}\\\\f=\dfrac{336}{4\times 3.1\times 10^{-2}}\\\\f=2709.67\ Hz\\\\f=2.7\ kHz

So, the fundamental frequency of can is 2.7 kHz. Hence, this is the required solution.

7 0
3 years ago
Stand next to a partner so that you are side-by-side. Each of you should hold your left arm out to the side and then point with
riadik2000 [5.3K]

Answer:

They would be pointing in the same direction

Explanation:

If they were facing each other then it may seem like they are pointing in different directions they would still point the same way.

5 0
2 years ago
You suspect that a power supply is faulty, but you use a power supply tester to measure its voltage output and find it to be acc
ValentinkaMS [17]

Answer:

Load

Explanation:

A normal power supply can deliver up to certain amount of power to a load. The output power can be calculated multiplying Voltage (V) x Current (A). It happens that after a certain period of time, the power source's main components begin to wear, thus losing its ability to deliver its nominal power. Normally, when no load its connected to the source, you will get the operating Voltage, but when the load demands power, the ability to deliver power to it may fail to reach nominal levels. When connected, there may be voltage drops (thus, less power output) causing malfunctions turning it into a non-operative power supply.

3 0
3 years ago
Two positive charges are labeled q Subscript 1 baseline and q Subscript 2 baseline are 0.1 m apart. Two positively charged parti
Snowcat [4.5K]

Answer:

Explanation:

Let that point be at a distance x from q1

Then Kq1/x^2= Kq2/ (s-x)^2

Taking square roots and simplifying, x =s /[1+(q2/q1)^0.5]

Assuming an identical distance, the rigidity of Q on 2Q is equivalent in value to the rigidity of 2Q on Q. for that reason, had the area R been stored an identical, the two forces could be equivalent. inspite of the shown fact that, via fact the area is being decreased, we could constantly consult with the equation we use to calculate those forces: F = ok(Q1xQ2)/(R^2) because R is squared and is being halved, the final result's that's it being divided by potential of a million/4. for that reason, the rigidity would be expanded by potential of four, and be 4F.

4 0
3 years ago
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