Answer:
T = 273 + (-50) = 273 – 50 = 223 K
R = 188.82 J / kg K for CO2
Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa
Density (Earth Atmosphere) = P / RT = 101600 / 287 x 291 = 1.216 kg /
Explanation:
example: humans (biosphere) can build a dam out of rock materials (geosphere) or water in a lake ( hydrosphere ) seeps into the cliff walls behind the dam becoming ground water ( geosphere) or evaporate into the air ( atmosphere)
The displacement is the distance from the beginning point to the ending point. The time was just to throw you off. If he walks 30m due west, and then 5m due east, his displacement would be 30-5=25m to the west.
Answer:
P = 1333.33 N
Explanation:
The pressure exerted by the boy on the floor can be calculated by the following equation:
![P = \frac{F}{A}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7BF%7D%7BA%7D)
where,
P = Pressure exerted by the boy = ?
F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)
A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)
A = 2(0.06 m x 0.25 m) = 0.03 m²
Therefore,
![P = \frac{40\ N}{0.03\ m^2}\\\\](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B40%5C%20N%7D%7B0.03%5C%20m%5E2%7D%5C%5C%5C%5C)
<u>P = 1333.33 N</u>
Since the car is at rest, the force experienced by car will be normal face(exerted by surface to which car is in contact) and weight of the car.
As the car is at rest, net force on the car should be zero.