1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Novay_Z [31]
4 years ago
13

The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -50 °C and 900 Pa, respect

ively. (a)Determine the density of the Martian atmosphere for these conditions if the gas constant for the Martian atmosphere is assumed to be equivalent to that of carbon dioxide. (b) Compare the answer from part (a) with the density of the Earth’s atmosphere during a spring day when the temperature is 18 °C and the pressure 101.6 kPa
Physics
2 answers:
Elza [17]4 years ago
6 0

Answer:

(a) The density of the Martian atmosphere is 0.021kg/m^3

(b) The density of the Martian atmosphere (0.021kg/m^3) is less than the density of the Earth's atmosphere (1.217kg/m^3)

Explanation:

(a) Density of Martian atmosphere (D) = P/RT

P = 900 Pa, R = 189 J/kgK, T = -50°C = -50+273 = 223K

D = 900/189×223 = 900/42,147 = 0.021kg/m^3

b) Density of Earth's atmosphere (D) = P/RT

P = 101.6kPa = 101.6×1000 = 101,600 Pa, R = 287 J/kgK, T = 18°C = 18+273 = 291K

D = 101,600/287×291 = 101,600/83,517 = 1.217kg/m^3

The density of Martian atmosphere is less than the density of the Earth's atmosphere

Sidana [21]4 years ago
4 0

Answer:

T = 273 + (-50) = 273 – 50 = 223 K

R = 188.82 J / kg K for CO2

Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / m^{3}

T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa

Density (Earth Atmosphere) = P / RT = 101600 / 287 x 291 = 1.216 kg / m^{3}

You might be interested in
A disk with a rotational inertia of 5.0 kg. m2 and a radius of 0.25 m rotates on a frictionless fixed axis perpendicu-
diamong [38]

Answer:1.6 rad/s

Explanation:

Given

moment of Inertia  of disk I=5 kg-m^2

radius of disc r=0.25 m

Force F=8 N

Torque T=I\alpha =F\cdot r

5\times \alpha =8\times 0.25

\alpha =0.4 rad/s^2

using

\theta =\omega _0\times t+\frac{\alpha t^2}{2}

\pi =0+\frac{0.4t^2}{2}

2\pi =0.4t^2

t^2=5\pi

t=\sqrt{5\pi }

t=3.96 s

\omega =\omega _0+\alpha t

\omega =0+0.4\times 3.96

\omega =1.58 rad/s\approx 1.6 rad/s

                         

3 0
4 years ago
A free-falling golf ball strikes the ground and exerts a force on it. Which sentences are true about this situation? A golf ball
Harlamova29_29 [7]

Answer:

The ground exerts an equal force on the golf ball

Explanation:

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

In this problem, object A is the golf ball while object B is the ground, so we can say that:

- the golf ball exerts a force on the ground

- the ground exerts an equal and opposite force on the golf ball

8 0
3 years ago
Read 2 more answers
A typical ten-pound car wheel has a moment of inertia of about 0.35kg⋅m2. The wheel rotates about the axle at a constant angular
QveST [7]

Answer:

The rotational kinetic energy of the rotating wheel is 529.09 J  

Explanation:

Given;

moment of inertia I = 0.35kg⋅m²

number of revolutions = 35.0

time of revolution, t = 4.00 s

Angular speed (in revolution per second), ω = 35/4 = 8.75 rev/s

Angular speed (in radian per second), ω = 8.75 rev/s x 2π = 54.985 rad/s

Rotational kinetic energy, K = ¹/₂Iω²

Rotational kinetic energy, K = ¹/₂ x 0.35 x (54.985)²

Rotational kinetic energy, K = 529.09 J  

Therefore, the rotational kinetic energy of the rotating wheel is 529.09 J  

7 0
3 years ago
Calculate the total mass of these letters in grams (mxe=131.29amu)
Lady_Fox [76]
We know avogadro's number = 6.023 x 10²³
1 amu = 1 atomic mass unit = 1/ (6.023 x 10²³) gm = 1.66 x 10⁻²⁴grams
<span>Now, to convert amu to grams,
 131.29 amu = 131.29 x 1.66 x 10</span>⁻²⁴grams
<span>= 2.18 x 10</span>⁻²²<span> grams is the answer</span>
4 0
4 years ago
Read 2 more answers
15 POINTS!!!! PLEASE ANSWER IM DOING AN ESSAY AND I ONLY HAVE 10 MINUST LEFT TO SEND IT IN!!!!
Colt1911 [192]

Answer:

Carbon dioxide is added to atmosphere naturally when organisms respire or decompose

Or through human activities, such as the burning of fossil fuels and forests and the production of cement.

3 0
3 years ago
Other questions:
  • If the diameter of the red marble is 3.0 cm, and by using the formula for volume, what is a good approximation of its volume? cm
    14·1 answer
  • If 50 mL of each of the liquids in the answer choices were poured into a 250 mL beaker, which layer would be directly above a sm
    8·1 answer
  • A rock is projected upward from the surface of the moon, at time t = 0.0 s, w a velocity of 30 m/s. The acceleration due to grav
    5·1 answer
  • A 2060 kg railroad flatcar, which can move with negligible friction, is motionless next to a platform. A 241 kg sumo wrestler ru
    9·1 answer
  • When an object is falling, its motion is most affected by air resistance when: Check all that apply.
    9·2 answers
  • Who was brilliant mathematician used the data of tycho brahe to prove accuracy of copernicus basic ideas of motion of planets?
    10·1 answer
  • Two objects that are not initially in thermal equilibrium are placed in close contact. After a while, the temperature of the cod
    9·1 answer
  • What is the equation for acceleration and what does each variable mean?
    10·1 answer
  • 3. What is Newton's 1st Law?
    6·1 answer
  • Which type of light is emitted from objects with the highest temperatures?.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!