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galina1969 [7]
3 years ago
9

A element or compound which occurs naturally in the earth

Chemistry
1 answer:
sashaice [31]3 years ago
5 0
An element or compound which occurs naturally in the earth is a mineral. Minerals are substances formed naturally in the Earth.They have a definite chemical composition and structure. For example, the minerals gold or diamonds you’d find by mining or panning for gold since they are found naturally in the Earth.
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What is the percent cr, by mass, in the steel sample? express your answer numerically as a percentage?
djverab [1.8K]
Given:3.40g sample of the steel used to produce 250.0 mLSolution containing Cr2O72−

Assuming all the Cr is contained in the BaCrO4 at the end. 
(0.145 g BaCrO4) / (253.3216 g BaCrO4/mol) x (250.0 mL / 10.0 mL) x (1 mol Cr / 1 mol BaCrO4) x (51.99616 g Cr/mol / (3.40 g) = 0.219 = 21.9% Cr
8 0
3 years ago
Read 2 more answers
What is radioactive decay?
swat32

Answer:

Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive. Three of the most common types of decay are alpha decay, beta decay, and gamma decay, all of which involve emitting one or more particles or photons.

Explanation:

7 0
3 years ago
The chemical properties of a substance can only be observed when it is changed into a different substance. True or False
HACTEHA [7]
I am pretty sure that the answer is true
6 0
3 years ago
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If I have an unknown quantity of gas at a pressure of 380 mmHg, a volume of 25 L, and a temperature of
Bess [88]

Answer:

                     0.5077 moles

Explanation:

Data Given:

                Moles  =  n  =  <u>???</u>

                Temperature  =  T  =  300 K

                 Pressure  =  P  =  380 mmHg = 0.50 atm

                 Volume  =  V  =  25 L

Formula Used:

Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

                 P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                 n  =  P V / RT

Putting Values,

                 n  =  (0.50 atm × 25 L) / (0.082057 atm.L.mol⁻¹.K⁻¹ × 300 K)

                 n  = 0.5077 moles

6 0
3 years ago
A 5.00 mL sample of hydrochloric acid is titrated with 0.1293 M ammonia (a base). If the titration required 28.15 mL of ammonia,
Sladkaya [172]

Answer:

1. C = 0.73 M.

2. pH = 0.14

       

Explanation:

The reaction is the following:

HCl + NH₃ ⇄ NH₄⁺Cl⁻

From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

n_{a} = n_{b}

Where "a" is for acid and "b" is for base.

The number of moles is:

n = C*V  

Where "C" is for concentration and "V" for volume.

C_{a}V_{a} = C_{b}V_{b}

C_{a} = \frac{0.1293 M*28.15 mL}{5.00 mL} = 0.73 M

Hence the initial concentration of the acid is 0.73 M.

The original pH of the acid is given by:

pH = -log([H^{+}])

pH = -log(0.73) = 0.14          

Therefore, the original pH of the acid is 0.14.

I hope it helps you!                  

4 0
2 years ago
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