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Licemer1 [7]
3 years ago
9

Math question, I appreciate ANY help! :)

Mathematics
1 answer:
pav-90 [236]3 years ago
8 0
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First and second place in the contest use a ratio to share a cash prize when first place pays $100 second please pay $60 how muc
Talja [164]

100/60 = x/36

Cross Multiply

3600 = 60x

x = 60

First place pays $60 when second place pays $36.

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

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A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall prac
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Maria will spin the arrow on the spinner 3 times.
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Well if those are the only 3 options of a segment, then there is a 1/3 chance of landing on A, then a 1/3 chance of landing on B, then a 1/3 chance of landing on C. Multiply the fractions together to get 1/27. However that isn't one of your answers. I'm thinking that the spinner has 4 sections, meaning 1/4 chance of A, then 1/4 chance of B, then 1/4 chance of C. Multiply these together to get 1/64, which is one of your answers. That's my input anyway
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15 bakers complete a big order in 24 hours. How many hours would it take 18 bakers to complete the same order?
MissTica

This is right!!!

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A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.
Oduvanchick [21]

Answer:

11402.66 m^{2}

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by \frac {0.5\pi d^{2}}{4}

Total area of semi circle will be 2\times\frac {0.5\pi d^{2}}{4}

Substituting 74 m for d and \pi as 3.14 we obtain

Total area semi-circle=2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}

Area of rectangle is given by the product of length and width

Rectangular area=96 m*74 m=7104 m^{2}

Total area of rectangular and semi-circles will be

4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}

Therefore, area of training field is 11402.66 m^{2}

6 0
3 years ago
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