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Aleks [24]
3 years ago
14

Each car has 5 wheels. There are 74 wheels. How many cars are there? How many wheels left over?

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer: 14 cars 4 left over

Step-by-step explanation:

74/5=14.8

14 x 5 = 70

4 wheels left over

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A square patio has an area of 122 square feet. How long is each side of the patio to the nearest 0.05?
jasenka [17]
Should be About 25 feet as your answer
3 0
2 years ago
The sum of four consecutive even integers is 256. what are the numbers?
Naily [24]

Answer:

61 , 63 , 65 , 67

Step-by-step explanation:

Let the least even number be denoted by x. The sum of the four consecutive even numbers would be:

(x) + (x + 2) + (x + 4) (x + 6) = 256

First, simplify. Combine all like terms:

x + x + x + x + 2 + 4 + 6 = 256

4x + 12 = 256

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 12 from both sides of the equation:

4x + 12 (-12) = 256 (-12)

4x = 256 - 12

4x = 144

Next, divide 4 from both sides of the equation:

(4x)/4 = (144)/4

x = 144/4

x = 61

61 is your first number. Find the next 3 consecutive numbers:

x = 61

x + 2 = 63

x + 4 = 65

x + 6 = 67

Check:

61 + 63 + 65 + 67 = 256

256 = 256

~

7 0
2 years ago
Please explain how to find the answer for this
FromTheMoon [43]
P(A \textrm{ and } B) = P(A) P(B|A)

P(A \textrm{ and } B) = \dfrac{3}{10} \cdot \dfrac{2}{5} = \dfrac{3}{25}

Second to last choice.


5 0
3 years ago
Which property is illustrated by the following statement? 50pts
Virty [35]

When multiplying numbers, it doesn't matter which number is first or second.

The correct answer is: Commutative Property of Multiplication

4 0
3 years ago
Read 2 more answers
Prove fermat's theorem for the case where f has a minimum at x0 (show f 0 (x0) = 0)
allochka39001 [22]
Suppose that some value, c, is a point of a local minimum point.

The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.

This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then: \frac{f(c + h) - f(c)}{h} \leq 0 \text{, where h is approaching 0 from the negative side}
As h approaches 0 from the positive side, then: \frac{f(c + h) - f(c)}{h} \geq 0

Thus, f'(c) = 0
6 0
3 years ago
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