So here we are given that the the velocity of the proton ( V ) is 2.0 ×
meters / second, with a magnetic field of strength 5.5 ×
tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....
F = q( V × B ),
F = q v B( sin ∅ ),
F = q v B( sin( 90 ) )
.... they form the following formula. Let's go through each of the variables in our formula here -
{ F = Magnetic Force ( which has to be calculated ), q = charge of proton (has charge of 1.602 ×
coulombs ), B = magnetic field }
All we have to do now is plug and chug,
F = ( 1.602 ×
)( 2.0 ×
)( 5.5 ×
) = ( About ) 1.8 ×
Newtons
Yes the movement of land forms is called the movment of plate tectonics. :) plz thnk me
AnswU GOT THIS!!!!!!!!!!!!!
Explanation:
Answer:
11,000 cm
Explanation:
Step 1: Given data
Width of the field (w): 17 meters
Length of the field (l): 38 meters
Step 2: Calculate the perimeter of the field
The field is a rectangle. We can find its perimeter (P) by adding its sides.
P = 2 × w + 2 × l = 2 × 17 m + 2 × 38 m = 110 m
Step 3: Convert the perimeter to centimeters
We will use the relationship 1 m = 100 cm.
110 m × (100 cm/1 m) = 11,000 cm
A have no potential energy