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schepotkina [342]
3 years ago
7

BRAINLIEST GETS 20 POINTS!!!(HELP!! :3)

Mathematics
2 answers:
Len [333]3 years ago
8 0
C

There is no way a equation will give you the same answer with different numbers (especially if the answer isn't zero, in this case it is 3)

hope this helps
n200080 [17]3 years ago
3 0
The answer is c because the y values can not repeat
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A survey asked people to name their favorite season. The results of the survey showed that 34% said spring and 15% said fall. Wh
max2010maxim [7]

Answer:

D. 29% and 22%

Step-by-step explanation:

The known percentages are 34% and 15%. Add these two together to get 49%. All four choices should add up to 100%. So subtract to find what remains:

100% - 49%

= 51%

We don't actually have enough information to determine the percents for summer and winter. BUT the only answer that adds up to 51% is answer D. 29% and 22%.

8 0
2 years ago
is it possible for a percent increase or decrease to be over 100% explain why or why not this is possible
Ivahew [28]
No because there has to be a remaining opposite persent
6 0
3 years ago
Whats 9x9-18+18-20+2?
zhuklara [117]

Answer:

9x^9-18

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
the perimeter of a rectangle is 160ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangl
Hitman42 [59]

Answer:

w = 80/9 ft.

L = 640/9 ft.

Step-by-step explanation:

L = length    w = width

2w = L/4  so 8w = L

160 = 2L + 2w

160 = 2(8w) + 2w

160 = 16w+2w

160 = 18w

80/9 = w

5 0
3 years ago
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now,  

\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
3 years ago
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