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Nitella [24]
2 years ago
9

Rachel runs 4 miles in 23 minutes. How many miles does she run per minute?​

Mathematics
1 answer:
KIM [24]2 years ago
8 0

Answer:

To calculate how many total miles Rachel runs per minute, setting up a unit rate, that is a rate with a denominator of 1, would be helpful.

Step-by-step explanation:

Use the current problem to determine a rate.

23 minutes/4 miles

Now, set up a unit rate.

1 minute/<em>x </em>miles = 23 minutes/4 miles

To solve for <em>x, </em>we can use simple division strategies. We divide 23 by 23 to receive 1 minute. Likewise, dividing the current milage by 23 would wield the correct unit rate. To do this, divide 4 by 23.

4/23 = 0.1739130434782609

Finally, simplify your answer to receive 0.17.

Therefore, Rachel runs ~0.17 miles per minute. (Note that this answer is only a rounded answer of her actual milage per minute)

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jek_recluse [69]
Yes you are correct, :)
6 0
3 years ago
32% of 1600 = 512
yaroslaw [1]

Answer:

  • 64%: 1024
  • 96%: 1536
  • 132%: 2112
  • 232%: 3712

Step-by-step explanation:

<u>64% of 1600</u>

  64% of 1600 = 2 × (32% of 1600) = 2×512

  64% of 1600 = 1024

<u>96% of 1600</u>

  96% of 1600 = 3 × (32% of 1600) = 3×512

  96% of 1600 = 1536

<u>132% of 1600</u>

  132% of 1600 = (100% of 1600) + (32% of 1600) = 1600 + 512

  132% of 1600 = 2112

<u>232% of 1600</u>

  232% of 1600 = (100% of 1600) + (132% of 1600) = 1600 +2112

  232% of 1600 = 3712

3 0
3 years ago
Read 2 more answers
What is the answer to this question?
irina [24]

Answer:

1. \frac{33}{40}  

2. \frac{19}{35}

Step-by-step explanation:

1. (\frac{5}{8} * \frac{5}{5}) + (\frac{1}{5} * \frac{8}{8}) = \frac{33}{40}

8 0
3 years ago
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected cont
DiKsa [7]
 Given that a display allows a customer to hook together any selection of components, one of each type. These are the types:
Receiver: Kenwood, Onkyo, Pioneer, Sony, Sherwood
CD player: Onkyo, Pioneer, Sony, Technics
Speakers: Boston, Infinity, Polk
Cassette: Onkyo, Sony, Teac, Technics:

Part (a):
In how many ways can one component of each type be selected?

The number of ways one type of receiver will be selected is given by 5C1 = 5
The number of ways one type of CD player will be selected is given by 4C1 = 4
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways one component of each type can be selected is given by 5 x 4 x 3 x 4 = 240 ways



Part (b):
In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

The number of ways of selecting a Sony receiver is 1
The number of ways of selecting a Sony CD player is 1
The number of ways one type of speakers will be selected is given by 3C1 = 3
The number of ways one type of cassette will be selected is given by 4C1 = 4

Therefore, the number of ways components can be selected if both the receiver and the compact disc player are to be Sony is given by 1 x 1 x 3 x 4 = 12



Part (c)
In how many ways can components be selected if none of them are Sony?

The number of ways one type of receiver that is not Sony will be selected is given by 4C1 = 4
The number of ways one type of CD player that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of speakers that is not Sony will be selected is given by 3C1 = 3
The number of ways one type of cassette that is not Sony will be selected is given by 3C1 = 3

Therefore, the number of ways that components can be selected if none of them are Sony is given by 4 x 3 x 3 x 3 = 108



Part (d):
In how many ways can a selection be made if at least one Sony component is to be included?

The total number of ways of selecting one component of each type is 240
The number of ways that components can be selected if none of them are Sony is 108

Therefore, the number of ways of selecting at least one Sony component is given by 240 - 108 = 132



Part (e):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains at least one Sony component?

The total number of ways of selecting one component of each type is 240
The number of ways of selecting at least one Sony component is 132

Therefore, the probability that a system selected at random contains at least one Sony component is given by 132 / 240 = 0.55



Part (f):
If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains exactly one Sony component? (Round your answer to three decimal places.)

The number of ways of selecting only a Sony receiver is given by 1 x 3 x 3 x 3 = 27
The number of ways of selecting only a Sony CD player is given by 4 x 1 x 3 x 3 = 36
The number of ways of selecting only a Sony cassette is given by 4 x 3 x 3 x 1 = 36

Thus, the number of ways of selecting exactly one Sony component is given by 27 + 36 + 36 = 99

Therefore, the probability that a system selected at random contains exactly one Sony component is given by 99 / 240 = 0.413
5 0
3 years ago
Write 4(x+2) using the distributive property
Damm [24]
Hey there! :D

The distributive property states that:

a(b+c)= ab+ac

4(x+2)= 4*x+4*2

4x+8 <== simplified expression

I hope this helps!
~kaikers
7 0
3 years ago
Read 2 more answers
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