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qaws [65]
3 years ago
13

What is the slope of a line that passes through (–12,15) and (0,4)?       

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0
Answer:  The slope is:  -\frac{11}{12} .
__________________________________________________
Explanation:
__________________________________________________
Given two points on the line:  (x₁, y₁) ;  and:  (x₂, y₂) ;

which are given:  (-12, 15) and (0, 4) ;  in which: 
________________________________________________________
                              x₁  = -12 ,  y₁  = 15 ,  x₂ = 0,  y₂ = 4 ;
_______________________________________________________
The slope, "m", is calculated as follows:
_______________________________________________________
   m = (y₂ − y₁) / (x₂ − x₁)  =  (4 − 15) / [0 − (-12)] ;
                                         =  (4 − 15) / (0 + 12) ;
                                         =    -11 / 12 .
_______________________________________________________
                            The slope, "m" is:   - 11/12 .
_______________________________________________________
dolphi86 [110]3 years ago
6 0
C is the answer -11/12
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8 0
3 years ago
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Korvikt [17]
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use identity  [cos(x)]^2 +[ sin(x)]^2 = 1 => cos(x) = √[1 - (sin(x))^2]

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square both sides

4[1 - (sin(x))^2] = 9 + 24 sin(x) + 16 (sin(x))^2

expand, reagrup and add like terms

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use quadratic formula and you get sin(x) = -0.93166 and sin(x) = -0.26834

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3 0
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Sum interior angle on a regular pentagon
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Answer:

540°

Step-by-step explanation:

Formula: note that n means nr of sides

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