What is the slope of a line that passes through (–12,15) and (0,4)?

2 answers:

7 0

Answer: The slope is: $-\frac{11}{12}$ .
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Explanation:
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Given two points on the line: (x₁, y₁) ; and: (x₂, y₂) ;

which are given: (-12, 15) and (0, 4) ; in which:
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                              x₁  = -12 , y₁  = 15 , x₂ = 0, y₂ = 4 ;
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The slope, "m", is calculated as follows:
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   m = (y₂ − y₁) / (x₂ − x₁) = (4 − 15) / [0 − (-12)] ;
                                         = (4 − 15) / (0 + 12) ;
                                         =    -11 / 12 .
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                            The slope, "m" is:   - 11/12 .
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