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-BARSIC- [3]
3 years ago
12

What is flammability?

Chemistry
2 answers:
Blababa [14]3 years ago
5 0
Flamibility is basically how flammable it is
Masteriza [31]3 years ago
3 0
Well, Flammability is: What happens when combustible liquids (liquids that can burn) ignite (catch on fire) and burn easily at normal working temperatures.

Hope I helped!

- Amber
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Please help!! I have 10 minutes left!!
Licemer1 [7]

Explanation:

1 is a process that occurs when gases in earth's atmosphere trap the sun's heat .

2 . heat in the atmosphere to warm the planet .

I only know the first too sorry ✨

8 0
3 years ago
Elements in a given period of the periodic table contain the same number of
leva [86]
Its C, Outermost Electrons.
4 0
3 years ago
Explain how original mass of dry ice compares with the mass of carbon dioxide gas?
MAVERICK [17]
The freezing temperature at a normal sea level air pressure is negative 78.5 degrees.
8 0
3 years ago
Given the equation C3H8(g) + O2(g) = CO2(g) + H2O(g) and that the enthalpies of formation for H2O(g) = -241.8 kJ/mol, CO2(g) = -
kari74 [83]

Answer: 72.4 kJ/mol

Explanation:

The balanced chemical reaction is,

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)  \Delta H=-2220.1kJ/mol

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]

\Delta H_{C_3H_8}=72.4kJ/mol

Therefore, the heat of formation of propane is 72.4 kJ/mol

7 0
3 years ago
A reaction produces 92.50 g FeSO4. How many grams of CuSO4 are necessary for this to occur?
xxMikexx [17]

Fe+CuSO4⟶Cu+FeSO4

Given that  

FeSO4 = 92.50 g  

Number of moles = amount in  g / molar mass

=92.50 g / 151.908 g/mol

=0.609 moles FeSO4

Now calculate the moles of CuSO4 as follows:

0.609 moles FeSO4 * 1 mole CuSO4 /1 mole FeSO4

= 0.609 moles CuSO4

Amount in g = number of moles * molar mass

= 0.609 moles CuSO4 * 159.609 g/mol

= 97.19 g CuSO4


3 0
3 years ago
Read 2 more answers
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