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-BARSIC- [3]
3 years ago
12

What is flammability?

Chemistry
2 answers:
Blababa [14]3 years ago
5 0
Flamibility is basically how flammable it is
Masteriza [31]3 years ago
3 0
Well, Flammability is: What happens when combustible liquids (liquids that can burn) ignite (catch on fire) and burn easily at normal working temperatures.

Hope I helped!

- Amber
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Use this paragraph Carlon is using two wooden blocks to model the movement of Earth's plates He pushes one block forward and the
tensa zangetsu [6.8K]

Answer:

a

Explanation:

6 0
3 years ago
One of the primary benefits of a survey is that they
snow_lady [41]

Answer:

B).  Allow efficient gathering of unobservable phenomena.

Explanation:

Surveys are described as the method of gathering information from a specified group of respondents for purposes like research or assessment of the truth of thoughts or opinions associated with a process.

As per the question, one of the most considerable benefits of the survey is that 'it allows the efficient gathering of unobservable phenomena'. The data associated with phenomena like stated preferences, behaviors, beliefs, and factual information are unobservable and can not be collected through observation but surveys help in doing so as well as in the assessment of the validity or reliability of the existing propositions about such phenomena. Thus, <u>option B</u> is the correct answer.

5 0
3 years ago
PLEASE ANSWER, I WILL GIVE BRAINLIEST AND THANKS!
zheka24 [161]

Answer:

Mass  = 8 g

Explanation:

Given data:

Mass of MgO formed  = 20 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

2Mg + O₂     →    2MgO

Number of moles of MgO:

Number of moles = mass/molar mass

Number of moles = 20 g/ 40 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of MgO and O₂ from balance chemical equation:

                     MgO         :            O₂

                        2            :            1

                      0.5          :        1/2×0.5 = 0.25 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Molar mass of O₂  is 32 g/mol

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

4 0
4 years ago
8 billion molecules of O2 gas
bixtya [17]
What do u want to solve?
6 0
4 years ago
what electronic transition in a hydrogen atom starting from n=7 energy level will produce infrared radiation with energy of 55.1
Lostsunrise [7]

Answer:

(<em>n</em> = 7) ⟶ (<em>n</em> = 4)

Explanation:

1. Convert the energy to <em>joules per mole of electrons</em>.  

<em>E</em> = 55.1 × 1000 = 55 100 J/mol

2. Convert the energy to <em>joules per electron </em>

<em>E</em> = 55 100/(6.022 × 10²³)

<em>E</em> = 9.150 × 10⁻²⁰ J/electron

3. Use the Rydberg equation to <em>calculate the transition </em>

Rydberg's original formula was in terms of wavelengths, but we can rewrite it to have the units of energy. The formula then becomes  

\Delta E = R_{\text{H}} (\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ n_{i}^{2}})

where  

R_{\text{H}} = the Rydberg constant = 2.178 × 10⁻¹⁸ J

n_{i} and n_{f} are the initial and final energy levels.

9.150 \times 10^{-20} = 2.178 \times 10^{-18}(\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 7^{2}})      

\frac{9.150 \times 10^{-20} }{2.178 \times 10^{-18}} = \frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 49}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01} + \frac{1 }{49 }

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.062 42}

n_{f}^{2} = \frac{1 }{ \text{0.062 42}}

n_{f}^{2} = 16.02

n_{f} = \sqrt{16.02}

n_{f} = 4.003 \approx 4

4 0
3 years ago
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