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2 years ago

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A weak acid, ha, has a p��a of 4. 524. If a solution of this acid has a ph of 4. 799 , what percentage of the acid is not io

nized? assume all h in the solution came from the ionization of ha.

1 answer:

insens350 [35]2 years ago

6 0

Answer:

highly endothermic

Explanation:

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When you step out of the bright sunshine into a dark movie theater, your vision gradually adjusts to the relative gloom. This pr

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The answer is A. intensity

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3 years ago

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Consider the reactionI2(g) + Cl2(g)2ICl(g)Using standard thermodynamic data at 298K, calculate the entropy change for the surrou

Georgia [21]

We know,

$\Delta H_{I_2(g)}=62.438\ KJ/mol\\\\\Delta H_{Cl_2(g)}= 0.0\ KJ/mol\\\\\Delta H_{ICl(g)}=17.78\ KJ/mol$

For given reaction, $I_2(g)+Cl_2(g)\ -->\ 2ICl(g)$

$\Delta H_{rxn}=2\Delta H_{ICl(g)}-\Delta H_{I_2(g)}-\Delta H_{Cl_2(g)}\\\\\Delta H_{rxn}=2(17.78)-0-62.438\ KJ/mol\\\\\Delta H_{rxn}=-26.878\ KJ/mol$

For , 2.41 moles of $I_2$ :

$\Delta H_{rxn}=2.41\times (-26.878)\ KJ\\\\\Delta H_{rxn}=-64.78\ KJ$

We know :

$\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K$

Hence, this is the required solution.

7 0

3 years ago

Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated temperatures. CH₄(????) + H₂O(????) ⇌ 3

sammy [17]

Answer:

6.2846

Explanation:

Given that:-

Concentrations at equilibrium :-

$[CH_4]=0.126\ M$

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$[CO]= 0.126\ M$

$[H_2]= 1.15\ M$

The equilibrium reaction is:-

$CH_4+H_2O\rightleftharpoons 3H_2+CO$

The expression for equilibrium constant is:

$K_{c}=\frac {\left [ H_2 \right ]^3\left [ CO \right ]}{\left [ CH_4 \right ]\left [ H_2O \right ]}$

Applying the values as:-

$K_c=\frac{1.15^3\times 0.126}{0.126\times 0.242}=6.2846$

<u>The equilibrium constant for the reaction is:- 6.2846</u>

5 0

3 years ago

60 kg of fuel was completely burnt for an experiment. The amount of heat energy was found to be 180000KJ. Calculate calorific va

FrozenT [24]

Answer:

3000 kJ/kg

Explanation:

The calorific value of a substance is the amount of heat produced per unit mass by the combustion of the substance.

It is given by:

$C=\frac{Q}{m}$

where

Q is the amount of heat released

m is the mass of the fuel

In this problem, we have:

m = 60 kg is the mass of fuel

$Q=180,000 kJ$ is the amount of heat released

Therefore, the calorific value of the fuel is:

$C=\frac{180,000}{60}=3000 kJ/kg$

6 0

3 years ago

If a gas furnace releases 420 kcal of heat energy, what is the energy in kilojoules? (1 cal = 4.184 J)

Igoryamba

Answer:
The furnace releases 1757280 J

Explanation:
We will do the conversion on two steps:
1- convert the kcal to cal
2- convert the cal to J

Step 1: converting kcal to cal
1 kcal is equivalent to 1000 cal. Therefore:
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Step 2: converting cal to J
We are given that:
<span>1 cal = 4.184 J
</span>Therefore:
420000 cal is equivalent to 420000 * 4.184 = 1757280 J

Hope this helps :)

8 0

3 years ago