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2 years ago

14

A weak acid, ha, has a p��a of 4. 524. If a solution of this acid has a ph of 4. 799 , what percentage of the acid is not io

nized? assume all h in the solution came from the ionization of ha.

1 answer:

insens350 [35]2 years ago

6 0

Answer:

highly endothermic

Explanation:

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Which of the following is the correct scientific notation for 0.0000782 g?

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The correct scientific notation is 7.82 x 105 g

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Write ashort note on the<br>first battle of<br>of panipat

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Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy

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Answer:

1. $S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

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3.The electron affinity of $Mg^{2+}$ is zero.

4. $O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

Explanation:

1.

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

2.

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

$Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

3.

The electronic configuration of Mg: $1s^{2}2s^{2}2p^{6}3s^{2}$

By the removal of two electrons from a magnesium element we get $Mg^{2+}$ ion.

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Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of $Mg^{2+}$ is zero.

4.

The ionization energy of $O^{2-}$ is follows.

$O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

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4 years ago

How many milliliters of C5H8 can be made from 366 mL C5H12 ?

zlopas [31]

The number of Ml of C₅H₈ that can be made from 366 ml C₅H₁₂ is 314.7 ml of C₅H₈

<u><em>calculation</em></u>

step 1: write the equation for formation of C₅H₈

C₅H₁₂ → C₅H₈ + 2 H₂

Step 2: find the mass of C₅H₁₂

mass = density × volume

= 0.620 g/ml × 366 ml =226.92 g

Step 3: find moles Of C₅H₁₂

moles = mass÷ molar mass

from periodic table the molar mass of C₅H₁₂ = (12 x5) +( 1 x12) = 72 g/mol

moles = 226.92 g÷ 72 g/mol =3.152 moles

Step 4: use the mole ratio to determine the moles of C₅H₈

C₅H₁₂:C₅H₈ is 1:1 from equation above

Therefore the moles of C₅H₈ is also = 3.152 moles

Step 5: find the mass of C₅H₈

mass = moles x molar mass

from periodic table the molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol

= 3.152 moles x 68 g/mol = 214.34 g

Step 6: find Ml of C₅H₈

=mass / density

= 214.34 g/0.681 g/ml = 314.7 ml

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