To answer this question, all you to do is to divide the mass by the molar mass and that should get you your moles.
<em>= 3.5 mol NH₄</em>
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In order to calculate the enthalpy of the reaction, we first calculate the heat released using the given formula.
Q = mc<span>ΔT
Q = 1000 x 4.184 x (35.65 - 24.85)
Q = 45187.2 J = 45.2 kJ
Now, we determine the moles of methane that were burned.
Moles = mass / Mr
Moles = 1.11 / (12 + 4)
Moles = 0.07
The enthalpy of a reaction is the energy released per mole, so the enthalpy in this case is:
</span>ΔH = 45.2 / 0.07
ΔH = 645.7 kJ/mol
So the whole point is that you need a abstract.
Answer:
Since the equation is balanced, So it have same number of oxygen in the reactants and well as product.
Oxygen in product = 8
Oxygen in reactant = 8
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