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11Alexandr11 [23.1K]

3 years ago

5

How many elements are in 2CaCO3 and C8H10N402

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

In 2CaCO3 there is 3 elements.

In C8H10N402 there is 3 elements.

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The equation X + Y yields

masha68 [24]

Most likely the equation yields a new compound XY. This is a synthesis reaction. <span>Synthesis reaction is a reaction where two or more substances combine to form a new compound. It is a reaction which releases energy in the form of heat and light. Therefore, it is an exothermic reaction.</span>

6 0

3 years ago

A negatively charged particle is attracted to A. All particles that are located close by. B. Only particles that are large. C. N

Dahasolnce [82]

Answer:

D. Positively charged particles

Explanation:

Negatively charged particles are attracted to positively charged particles and repelled against negatively charged particles

6 0

2 years ago

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Using the phase diagram for H2O what phase is water in at 1 atm pressure and 50oC? A. It is in the solid phase B. It is at its m

galina1969 [7]

Answer:

D.It is in the gas phase

Explanation:

hope it helps .

6 0

2 years ago

A sample of gallium Bromide GaBr2,weighing 0.165 g was dissolved in water and treated with silver nitrate AgNO3, and resulting t

tresset_1 [31]

<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

$\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol$

The chemical equation for the reaction of gallium bromide and silver nitrate follows:

$GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2$

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = $\frac{1}{1}\times 0.00072=0.00072moles$ of gallium nitrate

Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

$0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g$

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = $\frac{69.72}{193.73}\times 0.139=g$

To calculate the percentage composition of gallium in gallium bromide, we use the equation:

$\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100$

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

$\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%$

Hence, the percent gallium in gallium bromide is 30.30 %.

3 0

3 years ago

What is the mass of a sample of NH3 containing 7.20 x 10^24 molecules of NH3?

leva [86]

Answer:203

Explanation: just have to timez

4 0

2 years ago