Question

A certain strain of bacteria doubles in number each 20 days. Two of these bacteria are placed on

Answer 1

Answer:

Explanation:

We shall apply time dilution relation of relativity

t  = $\frac{t_0}{\sqrt{1-\frac{v^2}{c^2} } }$

$1000 = \frac{t_0}{\sqrt{1-\frac{v^2}{c^2} } }$

$1000 = \frac{t_0}{\sqrt{1-\frac{0.995^2}{1} } }$

t₀ = 1000 x .09987

= 99.87  days .

doubling time  = 20 days

no of doubling time in 20 days ;    n = 99.87 / 20

n = 4.9935

n = $n_0\times 2^n$ ; n₀ is initial number , n is number finally .

= 2 x 2⁴°⁹⁹³⁵

= 64 approx .